<u>Given:</u>
Volume of gas = 215 ml
Initial temperature T1 = 20C = 20 +273 = 293 K
Initial pressure P1 = 1 atm
Final pressure P2 = 1.5 atm
<u>To determine:</u>
The final temperature T2
<u>Explanation:</u>
Based on Gay-Lussac's Law:
P α T
Therefore we have the relation:
P1/T1 = P2/T2
T2 = P2T1/P1 = 1.5 *293/1 = 439.5 K
Converting from Kelvin to degrees C we have:
T2 = 439.5 - 273 = 166.5 C
Ans: The final temperature is 439.5 K or 166.5 C
valence electrons are the number of electrons in the outermost shell.
electron configuration is where the electrons are arranged in ascending order of energy shells
the electron configurations for the elements given are as follows
C - 2,4
Al - 2,8,3
Na - 2,8,1
Ca - 2,8,8,2
from the given elements, Aluminium has 3 electrons in its outermost shell.
answer is Aluminium
Answer:
The answer to your question is: Fluorine, Chlorine, Bromine, Iodine
Explanation:
Electron configuration ns² np⁵
We observe that this electron configuration finishes in "p". Elements from groups IIIA to VIIIA finish their electron configuration in "p".
Elements in Group IIIA finish in p¹
Group IVA finish in p²
Group VA finish in p³
Group VIA finish in p⁴
Group VIIA finish in p⁵
Group VIIIA finish in p⁶
Then, the list of elements with this electron configuration is:
Fluorine, Chlorine, Bromine, Iodine
Answer:
It might cave in on itself or collapse because of the change in pressure.