Specific Gravity of the fluid = 1.25
Height h = 28 in
Atmospheric Pressure = 12.7 psia
Density of water = 62.4 lbm/ft^3 at 32F
Density of the Fluid = Specific Gravity of the fluid x Density of water = 1.25 x 62.4
Density of the Fluid p = 78 lbm/ft^3
Difference in pressure as we got the differential height, dP = p x g x h dP = (78 lbm/ft^3) x (32.174 ft/s^2) x (28/12 ft) [ 1 lbf / 32.174 ft/s^2] [1 ft^2 /
144in^2]
Difference in pressure = 1.26 psia
(a) Pressure in the arm that is at Higher
P = Atmospheric Pressure - Pressure difference = 12.7 - 1.26 = 11.44 psia
(b) Pressure in the tank that is at Lower
P = Atmospheric Pressure + Pressure difference = 12.7 + 1.26 = 13.96psia
Answer:
6.4 Joules
Explanation:
For springs, Hooke's law states that;
F = ke
where F is a force applied, e is the extension and k is the spring constant.
Work done in a spring is the same as the potential energy stored in the spring. So that;
Work done = k
e = -
= 4 cm = 0.4 m
= 0
So that,
- = 0.4 m
Thus,
Work done = x 80 x
= 40 x 0.16
= 6.4
Work done = 6.4 J
The work done by the force on the spring is 6.4 Joules.
Here are a list of items I found.
some brushes
a armature
a permanent magnet
some slip rings
Answer:
1020
.00
1040.4
0
1061,208
1082.43
Explanation:
In this exercise we must calculate interest and add it to capital
2% of 1000
first month
interest = 1000 2/100
odds1 = 1020
second month
capital 1020
interest = 1020 0.02 = 20.4
odds2 = 1040.4
third month
capital = 1040.4
interest = 1040.4 0.02 = 20.808
odds3 = 1061,208
fourth month
capital = 1061,208
interest = 1061.208 0.02 = 21.22
odds = 1082.43
Answer: approximately 50%
Explanation: