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Naddika [18.5K]
3 years ago
8

An alternating current is supplied to an electronic component with a rating that the voltage across it can never, even for an in

stant, exceed 16 V. What is the highest rms voltage that can be supplied to this component while staying below the voltage limit?
A)8 sqrt 2 V

B) 16 sqrt 2 V

C) 256 V

D) 8
Physics
1 answer:
Vsevolod [243]3 years ago
7 0

Answer:

A) V_{rms}=8\sqrt{2} V

Explanation:

Maximum voltage =V_{max}=16 V

Maximum voltage and rms voltage are related to each other by

V_{max}=V_{rms} \times \sqrt{2} \\V_{rms}=\frac{V_{max}}{ \sqrt{2}}\\V_{rms}=\frac{16}{\sqrt{2}} \\V_{rms}=8\sqrt{2} V

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Images formed by a convex mirror are always ​virtual

Explanation:

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what is the mass of a pure platinum disk with a volume of 113 cm3? the density of platinum is 21.4 g/cm3
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V=m×d
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4 years ago
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Suppose the battery in a clock wears out after moving thousand coulombs of charge through the clock at a rate of 0.5 Ma how long
Ksivusya [100]

Answer:

Hello your question is poorly written below is the complete question

Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?

answer :

a) 231.48 days

b) n = 3.125 * 10^15

Explanation:

Battery moved 10,000 coulombs

current rate = 0.5 mA

<u>A) Determine how long the clock run on the battery. use the relation below</u>

q = i * t ----- ( 1 )

q = charge , i = current , t = time

10000 = 0.5 * 10^-3 * t

hence  t = 2 * 10^7 secs

hence the time = 231.48  days

<u>B) Determine how many electrons per second flowed </u>

q = n*e ------ ( 2 )

n = number of electrons

e = 1.6 * 10^-19

q = 0.5 * 10^-3 coulomb ( charge flowing per electron )

back to equation 2

n ( number of electrons ) = q / e = ( 0.5 * 10^-3 ) / ( 1.6 * 10^-19 )

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3 years ago
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Explanation:

for baseball

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What are the SI units for distance and time?
Anton [14]

Answer:

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