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Naddika [18.5K]
3 years ago
8

An alternating current is supplied to an electronic component with a rating that the voltage across it can never, even for an in

stant, exceed 16 V. What is the highest rms voltage that can be supplied to this component while staying below the voltage limit?
A)8 sqrt 2 V

B) 16 sqrt 2 V

C) 256 V

D) 8
Physics
1 answer:
Vsevolod [243]3 years ago
7 0

Answer:

A) V_{rms}=8\sqrt{2} V

Explanation:

Maximum voltage =V_{max}=16 V

Maximum voltage and rms voltage are related to each other by

V_{max}=V_{rms} \times \sqrt{2} \\V_{rms}=\frac{V_{max}}{ \sqrt{2}}\\V_{rms}=\frac{16}{\sqrt{2}} \\V_{rms}=8\sqrt{2} V

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Do all planetary systems look the same as our own?
Svet_ta [14]

Answer:

No

Explanation:

A planetary system consists of at least one star and non stellar objects revolving around it.

Our solar system has one star around which there are 8 planets. However there are star systems with more than one star. These systems are called binary systems. The size of stars also vary. They also vary by orbital configuration i.e, the planets have higher eccentricity than our solar system's. The planetary systems are also classified on the basis of the number of planets in them.

So, all planetary systems do not look the same as our own.

4 0
3 years ago
A positive point charge (q = +8.65 x 10-8 C) is surrounded by an equipotential surface A, which has a radius of rA = 2.97 m. A p
ella [17]

Answer:

r_B = 1.88 m

Explanation:

As we know that work done by electric force is given as

W_e = -q\Delta V

so here we know that charge is moving from

r_A = 2.97 m

to another position

so we will have

W_{AB} = \frac{kq_1q_2}{r_A} - \frac{kq_1q_2}{r_B}

-6.95\times 10^{-9} = (9\times 10^9)(8.65\times 10^{-8})(4.56\times 10^{-11})(\frac{1}{2.97} - \frac{1}{r_B})

-0.196 = (\frac{1}{2.97} - \frac{1}{r_B})

r_B = 1.88 m

7 0
3 years ago
PLS HELP MEEEE (NO LINKS PLEASE)
-Dominant- [34]
I think it could be D please tell me if I’m wrong I hope you have a wonderful day ❤️
5 0
2 years ago
Read 2 more answers
Describe the relationship between the Law of Conservation of Matter and balancing equations.
Yuliya22 [10]

Answer:

The mass of the products and reactants are the same on both sides of the equation.

The number of atoms of products and reactants are equal and hence it proves the law of conservation of mass.

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3 0
2 years ago
Read 2 more answers
If you use a force of 90 N to pick up a 10 pound bag of charcoal, what is the acceleration?
hjlf

Answer:

9ms^2

Explanation:

since ,Force=mass*acceleration

then, acceleration=force/mass

and, Force=90N

Mass=10pound

therefore, acceleration=90/10

=9ms^2

8 0
3 years ago
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