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TiliK225 [7]
3 years ago
15

A tractor pushes a log with a force of 6,000 N, if it is able to move it with an acceleration of 10m / s², how much mass does th

e body have?
Physics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

600kg

Explanation:

Given parameters:

Force  = 6000N

Acceleration  = 10m/s²

Unknown:

Mass of the body = ?

Solution:

To solve this problem, we apply newton's second law of motion:

    F = m x a

F is the force

m is the mass

a is the acceleration

 So;

          6000  = m x 10

         m  = 600kg

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The portion of earth underneath the crust containing the asthenosphere and the mesosphere is the
Hatshy [7]

Answer:

The portion of earth underneath the crust containing the asthenosphere  and mesosphere is outer core and inner core .

Explanation:

The outer core of the earth is ball of very hot metals . Its temperature is hot enough to melt all metals into liquid state . This is mainly composed of the melted metals nickel and iron . This has got got temperature between 4000 degrees to 9000 degrees .

Inner core is underneath the outer core ,Here the pressure is too high and this makes the metals squeezed and not even able to move like liquid . They are forced to vibrate just like a solid . This has got a thickness of 800 miles . The pressure here is comparably 3,000,000 times the air pressure at sea level.

6 0
4 years ago
The atomic mass of gold is 0.197 kg/mole. how many moles are in 0.566 kg of gold.
iogann1982 [59]

Explanation:

0.566kg *(1mol/0.197 kg)= 2.87 mol gold

note how the units cancel out, if the units do not cancel out (kg/kg=1) then u did something wrong

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3 years ago
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What variable is the dependent variable?<br><br> A. Time<br> B. Temperature
melomori [17]

Answer:

the answer is b temperature

6 0
3 years ago
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Imagine that you drop an object of 10 kg, how much will be the acceleration and
Lelu [443]

If you do this on Earth, then the acceleration of the falling object is 9.8 m/s^2 ... NO MATTER what it's mass is.

If its mass is 10 kg, then the force pulling it down is 98.1 Newtons. Most people call that the object's "weight".

4 0
3 years ago
If i = 1.70 A of current flows through the loop and the loop experiences a torque of magnitude 0.0760 N ⋅ m , what are the lengt
Alik [6]

Answer:

Length of the sides of the square loop is given by

s = √[(τ)/(NIB sin θ)]

Explanation:

The torque, τ, experienced by a square loop of area, A, with N number of turns around the loop and current of I flowing in the wire, with a magnetic field presence, B, and the plane of the loop tilted at angle θ to the x-axis, is given by

τ = (N)(I)(A)(B) sin θ

If everything else is given, the length of a side of the square loop, s, can be obtained from its Area, A.

A = s²

τ = (N)(I)(A)(B) sin θ

A = (τ)/(NIB sin θ)

s² = (τ)/(NIB sin θ)

s = √[(τ)/(NIB sin θ)]

In this question, τ = 0.076 N.m, I = 1.70 A

But we still need the following to obtain a numerical value for the length of a side of the square loop.

N = number of turnsof wire around the loop

B = magnetic field strength

θ = angle to which the plane of the loop is tilted, measured with respect to the x-axis.

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