Answer:
The altitude of geostationary satellite is 
Explanation:
Given that,
Radius of moon's orbit 
Time period 
We need to calculate the orbital radius of geostationary satellite is
Using formula of time period
Where, G = gravitational constant
M = Mass of earth
T = time period of geostationary satellite orbit
Put the value in to the formula
We need to calculate the altitude of geostationary satellite
Using formula of altitude
Where, R = radius of earth
a = radius of geostationary satellite
Put the value into the formula
Hence, The altitude of geostationary satellite is
The magnetic field of the wire will be directed towards west. Using right thumb rule one can get the direction of field lines.
The answer to this statement is true!
We have: Energy(E) = Planck's constant(h) × Frequency(∨)
Here, Planck's constant(h) = 6.626 × 10⁻³⁴ J/s
Frequency (∨) = 3.16 × 10¹² /s
Substitute the values into the expression:
E = (6.626 × 10⁻³⁴)(3.16 × 10¹²) J
E = 2.093 × 10⁻²¹ Joules
In short, Your Final answer would be 2.093 × 10⁻²¹ J
Hope this helps!
The answer is A. Newton's third law of motion states that for every action, there is an equal and opposite reaction. A rocket exerts a large force on the gas that is in the rocket chamber (action). The gas thus exerts a large reaction force forward on the rocket (reaction). The large reaction force is called thrust.
