If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
Answer:
243 in²
Step-by-step explanation:
Step 1. Calculate the<em> base and height </em>of the rectangle
We have two conditions:
(1) 2b+ 2h = 72 in
(2) b = 3h Substitute in (1)
2(3h) + 2h = 72 Remove parentheses
6h + 2h = 72 Combine like terms
8h = 72 Divide by 6
h = 9 in Substitute in(2)
b = 3 × 9
b = 27 in
Step 2. Calculate the area of the rectangle
A = bh
A = 27 × 9
A = 243 in²
The area of the rectangle is 243 in².
Question is not proper,Proper question is given below;
Nicholas buys 3/8 pound of cheese he put the same amount of cheese and three sandwiches how much cheese does Nicholas put on each sandwich
Answer:
Nichole can put
of cheese on each of his sandwich.
Step-by-step explanation:
Total Amount of cheese he has = ![\frac{3}{8} \ pound](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7D%20%5C%20pound)
Number of cheese sandwiches = 3
We need to find Amount of cheese does Nicole put on each of his sandwich.
Solution:
Amount of cheese on each sandwich can be calculated by dividing Total Amount of cheese he has with Number of cheese sandwiches.
framing in equation form we get;
Amount of cheese on each sandwich = ![\frac{\frac{3}{8}}{3}} = \frac{1}{8} \ pounds](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B3%7D%7B8%7D%7D%7B3%7D%7D%20%3D%20%5Cfrac%7B1%7D%7B8%7D%20%5C%20pounds)
Hence Nichole can put
of cheese on each of his sandwich.