1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ELEN [110]
3 years ago
14

1. Find the charge if the number of electrons is 4 x 10-18​

Physics
1 answer:
Marianna [84]3 years ago
4 0
22. The answer is 22.
You might be interested in
Which event demonstrates electromagnetic waves transferring energy?
Citrus2011 [14]

Answer:

Sun heating a car sitting in a parking lot

Explanation:

The sun heating a car sitting in a parking lot is an example of electromagnetic waves transferring energy.

  • Electromagnetic waves are produced from the vibration between electric and magnetic fields.
  • These waves can be propagated through vacuum with no particles inside of them.
  • The sun produces electromagnetic radiation through the process of nuclear fusion.
  • These radiations are used to warm the earth surface.
  • The sun heating a car sitting a parking lot is one vivid example.
4 0
2 years ago
Read 2 more answers
The density of a hippo is approximately 1030kg/m^3,so it sinks to the bottom of the freshwater lakes and rivers. A 1500kg hippo
hram777 [196]

Answer:

14,700 N

Explanation:

The hyppo is standing completely submerged on the bottom of the lake. Since it is still, it means that the net force acting on it is zero: so, the weight of the hyppo (W), pushing downward, is balanced by the upward normal force, N:

W-N=0 (1)

the weight of the hyppo is

W=mg=(1500 kg)(9.8 m/s^2)=14,700 N

where m is the hyppo's mass and g is the gravitational acceleration; therefore, solving eq.(1) for N, we find

N=W=14,700 N

8 0
3 years ago
An electron in a television tube is accelerated uniformly from rest to a speed of 8.4\times 10^7~\text{m/s}8.4×10 ​7 ​​ m/s over
stich3 [128]

Answer:

P=3.42×10^-6 J/s

Explanation:

From the kinematics of motion with constant acceleration we know that :  

vf^2=vi^2+2*a(xf-xi)

Where :

• vf , vi, are the the final and the initial velocity of the electron  

• a is the acceleration of the electron  

• xf , xi are the final and the initial position of the electron .

Strategy for solving the problem : at first from the given information we calculate the acceleration of the electron.  

Givens: vf = 8.4 x 10^7 m/s , vi, = 0 m/s , xf = 0.025 m and xi = 0 m  

vf^2 =vi^2+2*a(xf-xi)

vf^2-vi^2=2*a(xf-xi)

2*a(xf-xi)= vf^2-vi^2

          a = (vf^2-vi^2)/2(xf-xi)

Pluging known information to get :

a = (vf^2-vi^2)/2(xf-xi)

  = 1.411 × 10^17

From the acceleration and the previous Eq. we can calculate the final velocity of the electron but a new position xf = 0.01 m  

so,

vf^2 =vi^2+2*a(xf-xi)

vf^2 =5.312× 10^7

From the following Eq. we can calculate the time elapsed in this motion .  

xf =xi+vi*t+1/2*a*t

xf =xi+vi*t+1/2*a*t

  t=√2(xf-xi)/a

 t=3.765×10^-10 s

now we can use the power P Eq.  

 P=W/Δt => ΔK/Δt  

Where: the work done W change the kinetic energy K of the electron ,

ΔK=Kf-Ki=>1/2*m*vf^2-1/2*m*vi^2

P=1/2*m*vf^2-1/2*m*vi^2/Δt

P=3.42×10^-6 J/s

6 0
3 years ago
A 75-g bullet is fired from a rifle having a barrel 0.540 m long. Choose the origin to be at the location where the bullet begin
Mashutka [201]

The given question is incomplete. The complete question is as follows.

A 75-g bullet is fired from a rifle having a barrel 0.540 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is 14,000 + 10,000x − 26,000x^{2}, where x is in meters. Determine the work done by the gas on the bullet as the bullet travels the length of the barrel.

Explanation:

We will calculate the work done as follows.

     W = \int_{0}^{0.54} F dx

         = \int_{0}^{0.54} (14,000 + 10,000x - 26,000x^{2}) dx

         = [14000x + 5000x^{2} - 8666.7x^{3}]^{0.54}_{0}

         = 7560 + 1458 - 1364.69

         = 7653.31 J

or,      = 7.65 kJ       (as 1 kJ = 1000 J)

Thus, we can conclude that the work done by the gas on the bullet as the bullet travels the length of the barrel is 7.65 kJ.

5 0
3 years ago
How does water get to the tops of the tallest trees against the force of gravity
alexira [117]
Water gets to the leaves in the tops of the tallest trees by something called the cohesion-tension theory. Water has two very unique properties called adhesion and cohesion. Cohesion is the tendency of water molecules to stick together with one another. The water sticks together, leaving no room for air, strengthening the "force" of the water going up the tree. The water also sticks to the sides of the xylem inside the tree. In addition to these properties, there are also the factors of negative and positive water potential. For more information, look up more details of the cohesion-tension theory. 
4 0
3 years ago
Read 2 more answers
Other questions:
  • A girl pushes a cart with a force of 10 N. if the cart has a mass of 5 kg, what is its acceleration?
    13·1 answer
  • In what states does water appear on earth and on other planets?
    11·2 answers
  • If different groups of scientist have access to the same data, how can they draw different conclusions?
    5·1 answer
  • A ring, seen from above, is pulled on by three forces. the ring is not moving. how big is the force f
    8·1 answer
  • Which two parameters can both be measured in meters
    15·2 answers
  • All of the following are environmental factors that affect human development except _____.
    6·1 answer
  • What do you call rocxs that form under intense heat and pressure
    14·1 answer
  • You work at a retail store. Recently, paychecks have had errors and there have been many employee complaints. You have been assi
    5·2 answers
  • ELE Review questions
    12·1 answer
  • Suppose a pendulum clock has been calibrated to be accurate in San Francisco, where g = 9.800 m/s2 . In Camrose, g = 9.811 m/s2
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!