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siniylev [52]
3 years ago
10

in hydraulic pressure the area of the larger piston is half of the smaller piston.if the force of 4000N is applied on the smalle

r piston.what is the distance covered by the train ?​
Physics
1 answer:
irina1246 [14]3 years ago
7 0

Answer:

The distance moved by the train is half the distance moved by the force

Explanation:

Given that the force applied to the smaller piston, F₂ = 4,000 N

The pressure in the area of the larger piston, A₁ = 2 × The pressure in the smaller piston, A₂

∴ A₁ = 2 × A₂

We have;

\dfrac{A_1}{A_2} =  \dfrac{2\cdot A_2 }{A_2} =2 = \dfrac{F_1}{F_2}

F₁ = 2·F₂ = 2 × 4,000 N = 8,000 N

F₁·d₁ = F₂·d₂

∴ 8,000 N ×d₁ = 4,000 N × d₂

d₁ = 1/2·d₂

∴ The distance moved by the train is half the distance moved by the force

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Answer:

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A mountain climber weighs 42.0 N. If he climbs a hill 100m high. Calculate the work done in joules​
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Answer:

The answer is 4200 J.

Explanation:

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A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a
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Answer:

\dfrac{dz}{dt}=0.65\ ft/s

Explanation:

Given that

x= 150 ft

\dfrac{dy}{dt}= 7\ ft/s

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From the diagram

z^2=x^2+y^2

When ,x= 150 ft and y= 14 ft

z^2=150^2+14^2

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z^2=x^2+y^2

By differentiating with respect to time t

2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}

z\dfrac{dz}{dt}= x\dfrac{dx}{dt}+y\dfrac{dy}{dt}

Here x is constant that is why

\dfrac{dx}{dt}=0

z\dfrac{dz}{dt}= y\dfrac{dy}{dt}

Now by putting the values in the above equation we get

150.74\times \dfrac{dz}{dt}=14\times 7

\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s

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Therefore the distance between balloon and observer increasing with 0.65 ft/s.

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