in hydraulic pressure the area of the larger piston is half of the smaller piston.if the force of 4000N is applied on the smalle
1 answer:
Answer:
The distance moved by the train is half the distance moved by the force
Explanation:
Given that the force applied to the smaller piston, F₂ = 4,000 N
The pressure in the area of the larger piston, A₁ = 2 × The pressure in the smaller piston, A₂
∴ A₁ = 2 × A₂
We have;
F₁ = 2·F₂ = 2 × 4,000 N = 8,000 N
F₁·d₁ = F₂·d₂
∴ 8,000 N ×d₁ = 4,000 N × d₂
d₁ = 1/2·d₂
∴ The distance moved by the train is half the distance moved by the force
You might be interested in
the solution for the oscillatory movement allows to find the result for the amplitude of the initial displacement is:
- The range of motion is: A = 4.44 cm
The oscillatory periodic motion of a system occurs when there is a recovered force, in the special case that this force is proportional to the displacement is called simple harmonic motion, which is described by the expression.
x = A cos (wt + Ф)
w² = k/m
where x is the displacement, A the amplitude, w the angular velocity, t the time, k the spring constant, m the mass, and Ф a phase constant determined by the initial conditions.
Let's find the angular velocity/
w=
w = 25.8 rad/s
Let's look for the constant Ф, as the system is released from rest its initial velocity is zero, for zero time. The definition of speed is:
v=
v= - A w sin (wt +Ф)
0 = -A w sin Ф
Ф= 0
They indicate that at a given instant of the time the velocity is v= 50.0 cm/s and it is in a position x= 4.00 cm, let us write the equations for this time
Position.
4.00 = A cos 25.8t
Speed.
50.0 = - At 25.8 sin 25.8t
To solve the system, ;et's square and add.
Cos² 25.8t =
sin² 25.8t =
1 =
A =
A= 4.44 cm
In conclusion using the solution for the oscillatory movement we can find the result for the amplitude of the initial displacement is:
The range of motion is: A = 444 cm
Learn more about oscillatory motion here: brainly.com/question/14311816
Answer:
The new self inductance is 3 times of the initial self inductance.
Explanation:
The self inductance of a solenoid is given by :
Where
N is number of turns per unit length
A is area of cross section
l is length of solenoid
If length and number of coil turns are both tripled,
l' = 3l and N' = 3N
New self inductance is given by :
So, the new self inductance is 3 times of the initial self inductance.