Answer:
Kinetic energy, E = 9.1 eV
Explanation:
It is given that,
At the first excited state of a particular atom is 5.7 eV above the ground state. The kinetic energy of the atom after the collision is 3.4 eV.
We need to find the kinetic energy of the electron just before the collision. The conservation of momentum will be followed here. The energy gets transferred from moving electrons to these atoms is 5.7.
Let E is the kinetic energy of the electron just before the collision. It is equal to :
E = 5.7 eV + 3.4 eV
E = 9.1 eV
So, the kinetic energy of the electron just before the collision is 9.1 eV. Hence, this is the required solution.
It is because gravity is not an independent force. Gravity comes as result of warped space time according to the theory of general relativity. Therefore we can’t feel gravity because it’s not a force that pulls or pushes.
(a) What is
the potential energy: PE = -G * M * m/r
Where: M is the mass of the earth which is 5.98 * 10^24 kg.
m is the mass of the satellite.
r is the space from the center of the earth to the satellite
To conclude this distance add the radius of the earth to the
altitude. Radius of the earth is 6.38 * 10^6 meters.
r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6
PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 =
4.71240095 * 10^9 J
(b) magnitude of the gravitational force exerted by the
Earth
Fg = G * M * m/r^2
Fg = 6.67 * 10^-11 * 5.98 * 10^24 * 99/(8.38 * 10^6)^2 =
562.3078873 N
(c) There are no other forces that the satellite exert on
the Earth. So therefore, it is 0.
Answer:
the pressure exerted by the object is 392,000 N/m²
Explanation:
Given;
mass of the object, m = 8 kg
area of your finger, A = 2 cm² = 2.0 x 10⁻⁴ m²
acceleration due to gravity, g = 9.8 m/s²
The pressure exerted by the object is calculated as;
Therefore, the pressure exerted by the object is 392,000 N/m²
Answer:
<h2>The answer is 4 s</h2>
Explanation:
The time taken can be found by using the formula
where
d is the distance
v is the velocity
From the question we have
We have the final answer as
<h3>4 s</h3>
Hope this helps you
