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MariettaO [177]
3 years ago
12

Suppose that the radius of the circular path is r when the speed of the rocket is v and the acceleration of the rocket has magni

tude a. If the radius and speed are increased to 2r and 2v respectively, what is the magnitude of the rocket's subsequent acceleration?
a) 3 B) 2a C) a D) 4a E) 8a
Physics
1 answer:
SCORPION-xisa [38]3 years ago
4 0

Answer:

A3

Explanation:

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Please answer the following question!
Semmy [17]

Answer:

0

Explanation:

the momentum will always be 0 when it is at rest because the object isnt moving!

Hope this helped!

6 0
2 years ago
A penny is made of the element zinc
AnnyKZ [126]

Answer:

Explanation: what is the question?

5 0
3 years ago
Explain the expression “light travels at a speed”.
prohojiy [21]
We can’t exactly measure how fast speed is traveling .
8 0
3 years ago
Read 2 more answers
A triangular plate with a non-uniform areal density has a mass M=0.500 kg.
Vikki [24]

For  "A triangular plate with a non-uniform areal density has a mass M=0.500 kg...." the period of the oscillations.

T = 1.2042s

<h3>What is the period of the oscillations.?</h3>

The process of repeating variations of any quantity or measure about its equilibrium value in time is referred to as oscillation. Oscillation is defined as this process. Alternating between two values or revolving around a central value is another way to describe oscillation, which is a periodic fluctuation of a substance.

Generally, the equation for moment of inertia is  mathematically given as

T = 2 π √( I / mgd )

Therefore, a moment of inertia

I = 9.00×10-3 + md^2 ;

I=9.00*10^{-3}+ 0.5 * 0.3^2

I=0.054

T = 2π \sqrt{( 0.054 / (0.5 *9.8 * 0.3 )}

T = 1.2042s

In conclusion, the period of the oscillations.

T = 1.2042s

Read more about the period of the oscillations.

brainly.com/question/14394641

#SPJ1

3 0
2 years ago
A team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 19.0 kg, and the
marysya [2.9K]

(a) The total mass of the dogs is:

m_d = 8 \cdot (19.0 kg)=152.0 kg

The mass of the sled is:

m_s=210 kg

So, the total mass is: M=m_d+m_s=152 kg+210 kg=362 kg

The total force exerted by the dogs is:

F=8 \cdot (185 N)=1480 N

So, we can find the acceleration of the dogs by using Newton's second law:

a=\frac{F}{m}=\frac{1480 N}{362 kg}=4.09 m/s^2


(b) The acceleration we found at point (a) is also the acceleration of the sled, which has a mass of 210 kg. Therefore, the force exerted by the dogs on the sled is equal to the product between the mass of the sled and its acceleration:

F=m_s a=(210 kg)(4.09 m/s^2)=859 N

3 0
4 years ago
Read 2 more answers
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