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3 years ago

Round 1,819 to the nearest 100

Mathematics

1 answer:

Naddika [18.5K]3 years ago

6 0

Answer:

1,800

Step-by-step explanation:

1,819

----^

1 is less than five so you round down even if you round the 19 to 20 it would still be needed to round down because it is less than 50.

Hope this helps, have a good day! :)

(Brainliest would be appreciated?)

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What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 1080 mL of a 50 per cent solutio

Jlenok [28]

Answer: 480 mL, 600 mL

Step-by-step explanation:

Given

The concentration of the first acid is 75%

The concentration of the second acid is 30%

The final mixture has a concentration of 50%

The final volume is 1080 mL

Suppose x and y be the volume of the first and second acid

$\therefore x+y=1080\quad \ldots(i)\\0.75x+0.3y=0.5\times 1080\quad \ldots(ii)$

Solving the above equations we get

$x=480,y=600$

So, the quantity of the first acid is 480 mL and 600 mL for the second mixture.

6 0

2 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago

HELP HELP WITH THIS PLZ

lawyer [7]

10•10•10=1,000=10^3
1,608 divided by 1,000 equals 1.608

3 0

2 years ago

FIRST GET BRAINIEST PERIODTT TYSMMSMSMMSM

ValentinkaMS [17]

4+4+6+6=12+8=20

hope this helps

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