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Nana76 [90]
3 years ago
6

Can neptune sustain life?

Chemistry
2 answers:
mr_godi [17]3 years ago
8 0
No Neptune cannot sustain life.
Kay [80]3 years ago
6 0
No its cold mate and its a gas giant so yea...
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concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature
blondinia [14]

Answer:

82.0 mL

Explanation:

Step 1: Given data

  • Concentration of concentrated acid (C₁): 12.2 M
  • Volume of concentrated acid (V₁): ?
  • Concentration of dilute acid (C₂): 1.00 M
  • Volume of dilute acid (V₂): 1.00 L

Step 2: Calculate the required volume of the concentrated acid

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated acid using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.00 M × 1.00 L / 12.2 M = 0.0820 L = 82.0 mL

4 0
2 years ago
How many atoms are in 58.93 grams of cobalt (Co)?
Vadim26 [7]
If you have 58.93g of Co it means that you only have 1 mol (use a periodic table to find the answer, if you had more find it by proportion, it's easier). 
There's 6.022 x 10^23 atoms per mol so you have 6.022 x 10^23 atoms of Co.
(once again if you had more mol, you could find the answer by proportions).
7 0
3 years ago
Please show work:<br> Question below
ozzi

Answer:

b) 2.0 mol

Explanation:

Given data:

Number of moles of Ca needed = ?

Number of moles of water present = 4.0 mol

Solution:

Chemical equation:

Ca + 2H₂O     →      Ca(OH)₂ + H₂

now we will compare the moles of Ca and H₂O .

                          H₂O        :        Ca                

                             2           :        1

                             4.0           :       1/2×4.0 = 2.0 mol

Thus, 2 moles of Ca are needed.      

         

3 0
2 years ago
Nh3 is a weak base (kb = 1.8 × 10–5 m) and so the salt nh4cl acts as a weak acid. what is the ph of a solution that is 0.013 m i
ankoles [38]
First, we need to get the value of Ka:

when Ka = Kw / Kb 

we have Kb = 1.8 x 10^-5 

and Kw = 3.99 x 10^-16  so, by substitution:

Ka = (3.99 x 10^-16) /  (1.8 x 10^-5) = 2.2 x 10^-11

by using the ICE table :

                 NH4+  + H2O →NH3 +  H+
intial          0.013                       0         0 

change       -X                          +X      +X

Equ        (0.013-X)                      X         X

when Ka = [NH3][H+] / [NH4+] 

by substitution:

2.2 x 10^-11 = X^2 / (0.013 - X)  by solving this equation for X

∴X = 5.35 x 10^-7

∴[H+] = X = 5.35 x 10^-7

∴PH = - ㏒[H+]
 
        = -㏒(5.35 x 10^-7)
        = 6.27
6 0
3 years ago
The s orbital can hold
malfutka [58]

Answer:

B. Two electrons

Explanation:

Since the S orbital is closest to the nucleus and it only has one orbital, it can only hold 2 electrons

7 0
3 years ago
Read 2 more answers
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