Answer:
m= 29.645 g
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Given data:
density of wood = 0.77 g/cm³
volume= 38.5 cm³
mass= ?
Solution:
d= m/v
m= d × v
m= 0.77 g/cm³× 38.5 cm³
m= 29.645 g
Answer:
2.53×10²³ atoms
Explanation:
To solve this, convert grams to moles and moles to atoms.
To convert grams to moles, use the molar mass of C₁₂H₂₂O₁₁ (342.296 g/mol). Divide the mass by the molar mass to get moles. Moles = 0.4207
To convert moles to atoms, use Avogadro's number (6.022×10²³ atoms/mol). Multiply moles by Avogadro's number to get atoms. Atoms = 2.53×10²³
<span>Kwang Jeon observed that Amoeba had been attacked by a bacterial infection, and lots of the Amoeba had
died. However, some survived and continued to reproduce. After investigating the remaining
Amoeba and their offspring, he noticed they were very healthy. He thought maybe they were able to
fight off the bacteria, but instead, he found they were still infected with the bacteria but were not
dying. The bacteria were no longer making the Amoeba sick. Then, he killed off the bacteria using
antibiotics and was surprised to see that the Amoeba also died. It seemed the Amoeba and bacteria
had formed a relationship in which they both needed each other to survive. After researching, Jeon
found that the bacteria made a protein that the Amoeba needed to survive. </span>
Answer:
Half life = 1 / k[Ao]
Explanation:
From:
1/ [A] = kt + 1/ [Ao]
Isolating t on its own, we have:
kt = 1 / [A] - 1 / [Ao]
t = 1 / [Ao] / k
Re-arranging we have:
t = 1 / k [Ao]
The t represents the t=half life of the second order reaction and the formula can be re-written as:
t1/2 = 1 / k [Ao]
This is so because second order reaction decreases at a much faster rate than zero and first order reactions and there slopes decreases to zero at a much faster rate.
B. Particles of metallic structure begin to vibrate faster as they absorb.
C. Metals have a larger number of freely moving electrons.
D. Metals have high densities.
