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stira [4]
3 years ago
7

Who was pedro infante?????

Physics
2 answers:
lys-0071 [83]3 years ago
5 0

Answer: Pedro Infante Cruz (Spanish: [ˈpeðɾo iɱˈfante]; 18 November 1917 – 15 April 1957) was a Mexican actor and singer. Hailed as one of the greatest actors of the Golden Age of Mexican cinema, he is considered an idol in Mexico and other Latin American countries such as Venezuela, Guatemala and Peru.

Explanation:

Anettt [7]3 years ago
3 0

Answer:

Pedro Infante Cruz was a Mexican actor and singer. Hailed as one of the greatest actors of the Golden Age of Mexican cinema, he is considered an idol in Mexico and other Latin American countries such as Venezuela, Guatemala and Peru. He along with Jorge Negrete and Javier Solís are considered the best ranchera singers. Infante was born in Mazatlán, Sinaloa, but raised in nearby Guamúchil. He died on 15 April 1957 in Mérida, Yucatán, in a plane crash during a flight en route to Mexico City, after an engine failed on takeoff. His remains were later identified by a bracelet found.

His film career began in 1939 with him appearing in more than 60 films - 30 of them with his brother Ángel Infante, and starting in 1943 he recorded about 350 songs. For his performance in the movie Tizoc, he was awarded the Silver Bear for Best Actor at the 7th Berlin International Film Festival.

Resources: https://en.wikipedia.org › wiki › Pedro_Infante

<em>Hope this helps : D</em>

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Two charged particles are accelerated through a uniform electric field and zero magnetic field, then enter a region with zero el
Mrac [35]

Answer:

Explanation:

In magnetic field , charged particle will have circular path . Let the radius of their circular path be r₁ and r₂ . Let their velocity at the time of entering magnetic field be v₁ and v₂ .

The velocity with which they will come out of electric field can be measured from following equation

Eq = 1/2 m v²  , E is electric field , q is charge on the particle , m is mass and v is velocity .

v² = 2Eq / m

radius of circular path can be measured by the following expression

m v² / r = Bqv

2Eq / r = Bqv

r = 2Eq / Bqv

= 2E / Bv

r² = 4E² / B²v²

= 4E²m / B²x 2Eq

since E , B and q are constant

r² = K . m

r₂² / r₁² = m₂ / m₁

1.5²

m₂ / m₁ = 1.5²

= 2.25

6 0
3 years ago
I need help with 2 questions . Please help c:
dezoksy [38]
A) According to the nebular theory, the Solar System formed from a huge gaseous nebula which at a certain point was perturbated. Atoms and molecules started colliding, forming planetesimals (a sort of big rocks). The planetesimals were attracted to each other by gravity, forming bigger warm almost spherical objects called protoplanets, which at the end cooled down forming planets.
Therefore the correct answer is "all of the above".

b) The planets closer to the Sun were (and still are) subject to higher temperatures, due to their close distance to the Sun. In these conditions, rocky materials undergo condensation, while iced gaseous materials undergo vaporization. In the outer parts of the Solar System temperatures are too low to allow these transformations.
The correct answer is again "all of the above".
8 0
3 years ago
a 1000kg car uses a breaking force of 10,000N to stop in two second. What is the change in momentum of the car?
gayaneshka [121]

Answer:

ΔP =  20000 N s

Explanation:

To solve this problem we use the relation between momentum and moment

         I = Δp

let's calculate the momentum

         I = ∫F dt

if we use the average force

       I = F t

       I = 10000 2

       I = 20000 N s

therefore with the first equation

        ΔP = I = 20000 N s

8 0
3 years ago
calculate the time (in years) it would take to send a message to the Galactic Capitol located at the center of our Milky Way gal
Alinara [238K]

Answer:

The total time is \bf{52850~Yr}.

Explanation:

Given:

The distance between Galactic Capitol and Earth is, d = 2.5 \times 10^{20}~m

The speed of light is, c = 3 \times 10^{8}~m/s

The time taken by the message to reach and come back to Earth is given by

t &=& \dfrac{2d}{c}\\~~&=& \dfrac{2(2.5 \times 10^{20}~m)}{3 \times 10^{8}~m/s}\\~~&=& 1.6 \times 10^{12}~s\\~~&=& \dfrac{1.6 \times 10^{12}~s}{(86400 \times 365)~s}~Yr\\~~&\approx& 52849~Yr

In addition they take 1 year to decide to reply.

Thus, the total time is 25850~Yr.

7 0
4 years ago
In Wagner’s opera Das Rheingold, the goddess Freia is ransomed for a pile of gold just tall enough and wide enough to hide her f
Vesna [10]

Answer:

Price=$7×10⁷

Explanation:

Step 1: Estimate the volume of the pile,

Step 2: Multiply it by the density to get its mass

Step 2: Then multiply the mass by the price per gram to get the total price

So

The average pile dimensions are=45.7×45×172.7

V=3.6*10^{5}cm^{3}\\  m_{g}=V_{p}=3.6*10^{5}*19.3=7*10^{6}g\\

Price=m×$10

Price=(7×10⁶)×$10

Price=$7×10⁷

5 0
3 years ago
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