Answer:
When two objects collide and stick together, what will happen to their speed, assuming momentum is conserved? They will move at the same velocity as whichever object was fastest initially. They will move at the same velocity of whichever object was slowest initially.
Explanation:
Answer:
w = 0.189 rad/ s
Explanation:
This exercise we work with the conservation of the moment, the system is made up of the merry-go-round and the child, for which we write the moment of two instants
Initial
L₀ = I₀ w₀
Final
= I w
L₀ = L_{f}
I₀ w₀ = I_{f} w
.w = I₀/I_{f} w₀
The initial moment of inertia is
I₀ = 500 kg. m2
The final moment of inertia
= 500 + m r²
I_{f} = 500 + 20 1.5
I_{f} = 530 kg m²
Initial angular velocity
w₀ = 0.20 rad / s
Let's calculate
w = 500/530 0.20
w = 0.189 rad / s
Answer:
Decreases
Explanation:
When an electron is released from rest in a region of space with nonzero electric field. And when the electrons move the electric potential energy of the system decreases because the kinetic energy increases and for the total energy to remain constant the potential energy must reduce.
An electron is accelerated in an electric field meaning its kinetic energy increases.
Answer:
see that for the same pressure the displaced height in each cylinder is different because its diameter is different.
Pascal's principle
Explanation:
The pressure on a system is given by the relations
P = ρ g h
P = F / A
where ρ is the density of the liquid, h the height and A the area
The expressions above we see that if for the same height the pressure is the same regardless of the shape of the cylinder.
With the second expression we see that if the system has a different area, the pressure is
P = ![\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BF_%7B1%7D%20%7D%7BA_%7B1%7D%20%7D%20%3D%20%5Cfrac%7BF_%7B2%7D%20%7D%7BA_%7B2%7D%20%7D)
where we use subscript 1 for one body and subscript 2 for the other body
F₁ = ![\frac{A_{1} }{A_{2} } F_{2}](https://tex.z-dn.net/?f=%5Cfrac%7BA_%7B1%7D%20%7D%7BA_%7B2%7D%20%7D%20%20F_%7B2%7D)
The cylinder displacement is
V = A h
where V is the volume and h the height, in general the liquids are incompressible therefore the displaced volume is constant in the two bodies
V = A₁ h₁ = A₂ h₂
![\frac{A_{1} }{A_2} = \frac{h_2}{h_1}](https://tex.z-dn.net/?f=%5Cfrac%7BA_%7B1%7D%20%7D%7BA_2%7D%20%3D%20%5Cfrac%7Bh_2%7D%7Bh_1%7D)
we substitute
F₁ =
F2
From here we see that for the same pressure the displaced height in each cylinder is different because its diameter is different.
If the diameter is the same, the offset height is the same