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USPshnik [31]
3 years ago
10

What is the volume of HCl gas required to react with excess magnesium metal to produce 6.82 L of hydrogen gas at 2.19 atm and 35

.0 °C?
2 HCl(g) + Mg(s) ? MgCl2(s) + H2(g)
Chemistry
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

Explanation:

2 HCl(g) + Mg(s) → MgCl₂(s) + H₂(g)

Let's calculate the quantity of mole of produced hydrogen with the Ideal Gases Law

P . V = n . R .T

2.19 atm . 6.82L = n . 0.082 . 308K

(2.19 atm . 6.82L) / (0.082 . 308K) = n

0.591 mol = n

1 mol of H₂ gas came from 2 mol of hydrochloric, so, 0.591 mol came from the double of mole

0.591 .2 = 1.182 mole of acid.

Molar mass of HCl = 36.45 g/m

1.182 mole are (36.45 g/m . 1.182g ) contained in 43.1 g

Density HCl = HCl mass / HCl volume

0,118 g/mL = 43.1 g / HCl volume

43.1 g / 0.118 g/mL = 365.3 mL (HCl volume)

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What is the mass in grams of 5.50 mol of sodium?
Zolol [24]

Answer:

126.5g

Explanation:

n=<u>m</u><u> </u>

M

where n is moles

m is mass of substance

M is molar mass

molar mass of sodium is 23g/mol

m=nM

m=5.5(23)

m=126.5

8 0
3 years ago
Which of the following is one way creativity can help scientists?
postnew [5]

Answer:

One way creativity is helpful to scientists is when they need to come up with a experiment or cure for something their imaginastion is very helpful. The reason for that is with creativity they could get answers much quicker!

Explanation:

7 0
3 years ago
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the red line observed in the line spectrum for hydrogen has 3.03x10^-19J, what is the wavelength, in nm, of this?
djverab [1.8K]

Answer:

λ = 6.5604 x 1016 nm

Explanation:

Given Data:

The energy of the red line in Hydrogen Spectra = 3.03 x 10-19

Formula to calculate Wave length

E= hv

Where E is Energy

h is Planks Constant = 6.626 x 10–34 J s

v is frequency

In turn

v= c/ λ

where c is speed of light = 3.00 x 108 m s–1

λ is wavelength = to find

Solution:

Formula to be Used:

E= hv………………………… (1)

Putting the value v in equation 1

               E= h c/ λ…………………… (2)

Put the value in equation 2

3.03 x 10-19 J  = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) / λ ……………………….(3)

By rearranging equation 3

λ = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) /3.03 x 10-19  J

λ = 6.5604 x 107 m

The answer is in “m”

So we have to convert it into nm

So for this to convert “m” to “nm” multiply the answer with 109

λ = 6.5604 x 107 x 109

λ = 6.5604 x 1016 nm

6 0
3 years ago
When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of
Anastaziya [24]
Given: C3H8(g) + O2(g) ----> CO2 (g) + H2O (g)

Step : Put a 3 in front of CO2 (g) to balance C

=> C3H8(g) + O2(g) ----> 3CO2 + H2O to balance H

Step 2: Put a 4 in front of H2O

=> C3H8 (g) + O2(g) -----> 3CO2 (g) + 4H2O (g)

Step 3: Given that there are 3*2 + 4 = 10 O to the right side, put a 5 in front of O2 to balance O:

=> C3H8(g) + 5O2(g) -----> 3CO2(g) + 4H2O(g)

You can verify that the equation is balanced.

So, the answer is that the coefficient in front of O2 is 5.
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3 years ago
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