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USPshnik [31]
3 years ago
10

What is the volume of HCl gas required to react with excess magnesium metal to produce 6.82 L of hydrogen gas at 2.19 atm and 35

.0 °C?
2 HCl(g) + Mg(s) ? MgCl2(s) + H2(g)
Chemistry
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

Explanation:

2 HCl(g) + Mg(s) → MgCl₂(s) + H₂(g)

Let's calculate the quantity of mole of produced hydrogen with the Ideal Gases Law

P . V = n . R .T

2.19 atm . 6.82L = n . 0.082 . 308K

(2.19 atm . 6.82L) / (0.082 . 308K) = n

0.591 mol = n

1 mol of H₂ gas came from 2 mol of hydrochloric, so, 0.591 mol came from the double of mole

0.591 .2 = 1.182 mole of acid.

Molar mass of HCl = 36.45 g/m

1.182 mole are (36.45 g/m . 1.182g ) contained in 43.1 g

Density HCl = HCl mass / HCl volume

0,118 g/mL = 43.1 g / HCl volume

43.1 g / 0.118 g/mL = 365.3 mL (HCl volume)

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1. Lithium, water, edible salt, chalk, Carbon, Lime, Nitrogen, Potassium, Oxygen,
Kaylis [27]

Answer:

Explanation:

An atom is the smallest unit of an element that can take part in a chemical reaction. Atoms (and there corresponding symbols) mentioned in the question are

Lithium ⇒ Li

Carbon ⇒ C

Nitrogen ⇒ N

Potassium ⇒ K

Oxygen ⇒ O

Iron ⇒ Fe

Chlorine ⇒ Cl

A compound is substance that contains two or more atoms that are chemically combined and can be represented with a chemical formula. The compounds (and there corresponding formula) mentioned in the question are

Water ⇒ H₂O

Edible salt (sodium chloride) ⇒ NaCl

Chalk (calcium carbonate) ⇒ CaCO₃

Lime (calcium oxide) ⇒ CaO

Iodides (such as sodium iodide and potassium iodide) ⇒ NaI and KI respectively

8 0
2 years ago
What is the mass of KOH found in a 785 mL of a 1.43 M solution of KOH
My name is Ann [436]

Molarity is defined as the ratio of number of moles to the volume of solution in litres.

The mathematical expression is given as:

Molarity = \frac{Number of moles}{volume of solution in litres}

Here, molarity is equal to 1.43 M and volume is equal to 785 mL.

Convert mL into L

As, 1 mL = 0.001 L

Thus, volume = 785\times 0.001 = 0.785 L

Rearrange the formula of molarity in terms of number of moles:

Number of moles =molarity\times volume of solution in litres

n = 1.43 M \times 0.785 L

= 1.12255 mole

Now,  Number of moles  = \frac{mass in g}{molar mass}

Molar mass of potassium hydroxide  = 56.10 g/mol

1.12255 mole  = \frac{mass in g}{56.10 g/mol}

mass in g = 1.12255 mole\times 56.10 g/mol

= 62.97 g

Hence, mass of KOH = 62.97 g



7 0
3 years ago
A student has an unknown sample. How can spectroscopy be used to identify the sample?
iogann1982 [59]

Answer: A. It can identify the elements in the sample.

Explanation: on edge

4 0
4 years ago
2 uniones iónicas y 2 covalentes, realizando las estructuras de Lewis correspondiente y averiguar la función del compuesto armad
posledela

Answer:

Cloruro de sodio y fluoruro de sodio.

Dióxido de carbono y monóxido de hidrógeno.

Explicación:

El cloruro de sodio y el fluoruro de sodio son los compuestos que tienen enlaces iónicos. Estos compuestos iónicos se utilizan para diferentes actividades de nuestra vida diaria. El cloruro de sodio se usa para cocinar y el fluoruro de sodio se usa en la pasta de dientes para limpiar nuestros dientes. El dióxido de carbono y el monóxido de hidrógeno son compuestos que tienen enlaces covalentes. El dióxido de carbono se usa en refrescos / refrescos y algunos otros líquidos que se pueden usar en la vida diaria. El monóxido de hidrógeno es el agua pura que bebemos todos los días en nuestra vida diaria y es muy importante para nuestra supervivencia.

7 0
3 years ago
A. Reaction with what gas in the atmosphere makes natural rain water slightly acidic? (2 points)
Vlada [557]

Answer:

See explanation

Explanation:

On the pH scale acidity ranges from pH values of 0-6.9. Natural rain water is slightly acidic due to the presence of carbon dioxide in the atmosphere which is an anhydride of carbonic acid.

CO2(g) + H2O(l) -------> H2CO3(aq)

B. The equations that turn sulfur to sulfuric acid are;

S(l) + O2(g) -----> SO2(g)

2SO2(l) + O2(g) -----> 2SO3(g)

SO3(g) + H2SO4(l) -----> H2S2O7(l)

H2S2O7(l) + H2O(l) ----> 2H2SO4(l)

-

At pH 6, H^+ concentration = 1 * 10^-6 M

At pH 2, H^+ concentration = 1 * 10^-2 M

Hence;

1 * 10^-2/1 * 10^-6

= 10^4 times more acidic

5 0
3 years ago
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