13.6) When any boat displaces a weight of water equal to its own weight, it floats.
Answer:
a) The flea's speed when it leaves the ground is
b) The flea move upward while it is pushing off
Explanation:
Hi
<u>Knwons</u>
Mass , Work and Force
a) Here we are going to use , so
a) Here we are going to use , so or approx.
Answer:
the correct answer is option C
To explain, I will use the equations for kinetic and potential energy:
<h3>Potential energy </h3>
Potential energy is the potential an object has to move due to gravity. An object can only have potential energy if 1) <u>gravity is present</u> and 2) <u>it is above the ground at height h</u>. If gravity = 0 or height = 0, there is no potential energy. Example:
An object of 5 kg is sitting on a table 5 meters above the ground on earth (g = 9.8 m/s^2). What is the object's gravitational potential energy? <u>(answer: 5*5*9.8 = 245 J</u>)
(gravitational potential energy is potential energy)
<h3>Kinetic energy</h3>
Kinetic energy is the energy of an object has while in motion. An object can only have kinetic energy if the object has a non-zero velocity (it is moving and not stationary). An example:
An object of 5 kg is moving at 5 m/s. What is the object's kinetic energy? (<u>answer: 5*5 = 25 J</u>)
<h3>Kinetic and Potential Energy</h3>
Sometimes, an object can have both kinetic and potential energy. If an object is moving (kinetic energy) and is above the ground (potential), it will have both. To find the total (mechanical) energy, you can add the kinetic and potential energies together. An example:
An object of 5 kg is moving on a 5 meter table at 10 m/s. What is the objects mechanical (total) energy? (<u>answer: KE = .5(5)(10^2) = 250 J; PE = (5)(9.8)(5) = 245 J; total: 245 + 250 = 495 J</u>)
To solve this problem it is necessary to apply the concepts related to the magnetic field.
According to the information, the magnetic field INSIDE the plates is,
Where,
Permeability constant
Electromotive force
r = Radius
From this deduction we can verify that the distance is proportional to the field
Then the distance relationship would be given by
On the outside, however, it is defined by
Here the magnetic field is inversely proportional to the distance, that is
Then,