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Angelina_Jolie [31]

3 years ago

14

the loss of a partical such as a proton as an atom tries to become stable is called A.) an isotope B.) Radioactive decay C.) Rad

iation D.) ionization

2 answers:

Arte-miy333 [17]3 years ago

4 0

The answer would be B

Ugo [173]3 years ago

4 0

: Radioactive Decay

~Sarah Robinsen

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Technician A says when diagnosing an overheating hydraulic system, be sure that the oil cooler is not plugged and the cooler’s f

mel-nik [20]

Answer:

Tech B is correct and Tech A is incorrect.

Explanation:

Here Tech A is wrong because when diagnosing an overheating hydraulic system, it is not necessary to un plugg the oil cooler rather it should be plugged to for proper diagnosis.

Technician B says running the hydraulic system at a lower operating temperature will reduce the possibly of oil oxidation is correct statement because at temperature oil's physical as well as chemical property tend to change.

Hence, Tech B is correct and Tech A is incorrect.

8 0

3 years ago

A plastic block of mass 0.20.2kg is initially at rest on a horizontal frictionless surface. A bullet of mass 1212 g is fired wit

Juli2301 [7.4K]

Answer:

94.29619%

Explanation:

$m_1$ = Mass of bullet= 0.012 kg

$m_2$ = Mass of block = 0.2 kg

$u_1$ = Initial Velocity of bullet= 550 m/s

$u_2$ = Initial Velocity of block = 0 m/s

$v_1$ = Final Velocity of bullet = 20 m/s

$v_2$ = Final Velocity of block

As the linear momentum of the system is conserved

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{0.012\times 550+0.2\times 0-0.012\times 20}{0.2}\\\Rightarrow v_2=31.8\ m/s$

Change in kinetic energy is given by

$\Delta K=\dfrac{1}{2}(m_1u_1^2-m_1v_1^2-m_2v_2^2)\\\Rightarrow \Delta K=\dfrac{1}{2}(0.012\times 550^2-0.012\times 20^2-0.2\times 31.8^2)\\\Rightarrow \Delta K=1711.476\ J$

Percentage change is given by

$\dfrac{\Delta K}{\dfrac{1}{2}m_1u_1^2}\times 100=\dfrac{1711.476}{\dfrac{1}{2}0.012\times 550^2}\times 100=94.29619\ \%$

The percent of the initial kinetic energy of the bullet block system is lost during the collision is 94.29619%

4 0

3 years ago

In 1990, a pizza with a radius of 18.0 m was made in South Africa. Suppose you make an air-filled capacitor with parallel plates

Mazyrski [523]

Explanation:

We have,

Radius of pizza, r = 18 m

Potential difference, V = 575 V

Stored electrical potential energy, E = 3.31 J

The area if an air-filled capacitor with parallel plates is equal to that of the pizza. It means, $A=\pi r^2=\pi (18)^2=1017.87\ m^2$

The stored potential energy in a capacitor is given by :

$E=\dfrac{1}{2}CV^2$

C is capacitance

$C=\dfrac{2E}{V^2}\\\\C=\dfrac{2\times 3.31}{(575)^2}\\\\C=2\times 10^{-5}\ F$

The formula of the capacitance of a parallel plate capacitor is given by :

$C=\dfrac{\epsilon_o A}{d}$

d is plate separation of this capacitor

$d=\dfrac{\epsilon_o A}{C}\\\\d=\dfrac{8.85\times 10^{-12}\times 1017.87}{2\times 10^{-5}}\\\\d=4.5\times 10^{-4}\ m$

4 0

3 years ago

What is the term for the force exerted on an object by another object?

marshall27 [118]

A: action force ... to which there is a reaction force

7 0

4 years ago

Which best explains why infrared waves are ineffective for treating cancer? They have frequencies that are too high to kill canc

Roman55 [17]

Infrared waves are ineffective for treating cancer because they do not transfer enough energy to destroy cancer cells.

<h3>Importance of high frequency waves</h3>

One of the uses of a high frequency wave is in the treatment of cancer. These high frequency waves transfer enough energy to destroy the cancer cells.

E = hf

where;

f is frequency of the wave

Infrareds have low frequency, and hence low energy.

Thus, infrared waves are ineffective for treating cancer because they do not transfer enough energy to destroy cancer cells.

Learn more about high frequency here: brainly.com/question/1807992

#SPJ1

5 0

2 years ago

Read 2 more answers