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3 years ago

Which statement correctly compares infrared light to ultraviolet light?

Physics

2 answers:

Sunny_sXe [5.5K]3 years ago

8 0

Infrared waves are further apart and ultra violeet are close together

san4es73 [151]3 years ago

7 0

Infrared light has a higher frequency and longer wavelength than ultraviolet light.

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Which of the following is not considered essential for an electronic device to be called a computer? A) network capable B) proce

balu736 [363]

Answer:

Explanation:

The full definition of a computer is

A computer is a machine(electronic device) that can be programmed to accept data (input), process it into useful information (output), and store it away (in a secondary storage device) for safekeeping or later reuse.

It is not necessary that a computer have network capacity, as far as it can process data into information, accept input and store results.

The correct option is A

7 0

4 years ago

Describe how you could conduct an experiment to quantify photosynthesis under different conditions, such as different amounts of

Mama L [17]

different amounts of sunlight can be conducted throughout the world but some special are

Explanation:

take bisc(*- calcoihvx to ordz which makes to easy

6 0

3 years ago

A NASCAR driver weighing 75 kg enters a corner with a radius of 155 meters. If his acceleration is 100 m/s2. What is tangential

Ymorist [56]

The tangential velocity of the car is 124.5 m/s

Explanation:

The centripetal acceleration of an object in uniform circular motion is given by:

$a=\frac{v^2}{r}$

where

a is the acceleration

v is the tangential velocity

r is the radius of the circle

For the car in this problem, we have:

$a=100 m/s^2$ is the centripetal acceleration

r = 155 m is the radius of the turn

Solving for v, we find the tangential velocity of the car:

$v=\sqrt{ar}=\sqrt{(100)(155)}=124.5 m/s$

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

3 0

3 years ago

A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a d

Mnenie [13.5K]

Answer:

Explanation:

Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

6 0

3 years ago

) each plate of a parallel-plate air-filled capacitor has an area of 0.0020 , and the separation of the plates is an electric fi

Dvinal [7]

I attached the full question.
We know that for a parallel-plate capacitor the surface charge density is given by the following formula:
$\sigma=\varepsilon_0 \frac{V}{d}$
Where V is the voltage between the plates and d is separation.
Voltage is by definition:
$V=Ed$
Voltage is analog to the mechanical work done by the force.
Above formula is correct only If the field is constant, and we can assume that it is since no function has been given.
The charge density would then be:
$\sigma=\varepsilon_0 \frac{Ed}{d}=\varepsilon_0E\\
\sigma= 8.85\cdot10^{-12}\cdot 2.1\cdot 10^6= 0.0000185\frac{c}{m^2}$
Please note that elecric permittivity of air is very close to elecric permittivity of vacum, it is common to use them <span>interchangeably</span>.

6 0

4 years ago