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fredd [130]
2 years ago
12

Which statement most completely defines a wave? *

Chemistry
1 answer:
Svetllana [295]2 years ago
4 0

Answer:

A wave transfers energy through a medium or empty space without transporting matter.

Explanation:

  • A wave is a transmission of a disturbance from one point known as the source to another.
  • Waves may transfer energy through a material medium or a vacuum without transporting matter.
  • Waves that transfer energy from one point to another through a material medium are known as mechanical waves.
  • Electromagnetic waves, on the other hand, are those that do not require a material medium for transmission, the transfer of energy is through a vacuum.
  • Waves can also be either transverse or longitudinal waves based on the vibration of particles relative to the direction of wave motion.
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If you have an altitude of 55 mi. (miles), which layer of the atmosphere are you in?
Kruka [31]

Answer: You would be in the D-region

The reason I understand this is because the D-region stands 55 miles in altitude, despite it will likely vanishes at night.

8 0
2 years ago
As part of a soil analysis on a plot of land, a scientist wants to determine the ammonium content using gravimetric analysis wit
jeka94

Answer:

Mass percentage of NH₄Cl = 3.54%

Mass percentage of K₂CO₃ = 1.01%

Explanation:

If a 200.0 mL aliquot produced  0.105 g of KB(C₆H₅)₄, then a 100.0 mL aliquot would produce 1/2 * 0.105 g = 0.0525 g of KB(C₆H₅)₄.

Therefore, mass of NH₄B(C₆H₅)₄ in the 100.0 ml aliquot = (0.277 - 0.0525)g = 0.2245 g

Number of moles of NH₄B(C₆H₅)₄ in 0.2245 g = 0.2245 g/ 337.27 g/mol = 0.0006656 moles

In 500 ml solution, number of moles present = 0.0006656 * 500/100 = 0.003328 moles.

From equation of the reaction; mole ratio of  NH₄⁺ and NH₄B(C₆H₅)₄ = 1:1

Similarly, mole ratio of  NH₄⁺ and NH₄Cl = 1:1

Therefore, moles of NH₄Cl in 500 ml sample = 0.003328 moles

Mass of NH₄Cl  = 0.003328 mol * 53.492 g/mol = 0.178 g

Mass percentage of NH₄Cl = (0.178/5.025) * 100% = 3.54%

Number of moles of KB(C₆H₅)₄ in 0.105 g (precipitated from 200.0 ml aliquot) = 0.105 g/ 358.33 g/mol = 0.000293 moles

In 500 ml solution, number of moles present = 0.000293 * 500/200 = 0.0007326 moles.

From equation of the reaction; mole ratio of  K⁺ and KB(C₆H₅)₄ = 1:1

Similarly, mole ratio of  K⁺ and K₂CO₃ = 2:1

Therefore, moles of K₂CO₃ in 500 ml sample = 0.0007326/2 moles =  0.0003663 moles

Mass of  K₂CO₃ = 0.0003663 mol * 138.21 g/mol = 0.05063 g

Mass percentage of K₂CO₃ = (0.05063/5.025) * 100% = 1.01%

7 0
3 years ago
Find the density of metal with a volume 4.0 cm and a mass of 8.0 grams.
olga_2 [115]
D=m/v

so,

d=8.0g/4.0cm

d=2

3 0
2 years ago
How do you think the flooding likely affected the ecosystem?
Lapatulllka [165]

Answer

raise/lower temp of certain ecosystems. Bring new predators/prey. Erode surrounding environment

Explanation:

5 0
2 years ago
Work is equal to the what used and multiplyed by the what over which the force was applied
Allushta [10]
W=Fd
Work is equal to the force multiplied by the distance travelled.
4 0
3 years ago
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