Answer:
v_f = 0.87 m/s
Explanation:
We are given;
F_avg = -17700 N (negative because it's backward)
m = 117 kg
Δt = 5.50 × 10^(−2) s
v_i = 7.45 m/s
Now, formula for impulse is given by;
I = F•Δt = - 17700 x 5.50 × 10^(−2) = - 973.5 kg.m/s
From impulse momentum theory, we know that;
Change in momentum of particle is equal to impulse.
Thus,
Δp = I = m•v_f - m•v_i
Thus,
-973.5= 117(v_f - 7.45)
Thus,
-973.5/117 = (v_f - 7.45)
-8.3205 + 7.45 = v_f
v_f = - 0.87 m/s
We'll take absolute value as;
v_f = 0.87 m/s
Answer:

Explanation:
<u>Dynamics</u>
When a particle of mass m is subject to a net force F, it moves at an acceleration given by

The particle has a mass of m=2.37 Kg and the force is horizontal with a variable magnitude given by

The variable acceleration is calculated by:


The instant velocity is the integral of the acceleration:


Integrating



Complete question
The complete question is shown on the first and second uploaded image
Answer:∈
Answer to first question is shown on the second uploaded image.
Part B the Answer is:
The ratio
is evaluated to be 49.99
Explanation:
The explanation is shown on the third ,fourth and fifth image.