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What role does carbon dioxide play for all living things

alexandr1967 [171]

Answer:

carbon dioxide plays an important part in vital plant and animal process, such as photosynthesis and respiration.

Explanation:

8 0

3 years ago

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If two objects of unequal mass collide, both objects will continue to move in the direction of

gayaneshka [121]

Assuming this is an elastic collision, they go in the direction of the object with more mass

3 0

3 years ago

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What is the available energy content, in joules, of a battery that operates a 2.00-W electric clock for 18 months

iren2701 [21]

Answer:

93312000 Joules

Explanation:

Energy can be explained as the capacity for doing work. And can be expressed as

E= pt....................eqn(1)

Where

E= Energy in Joules

P= power in Watt= 2.00W

t= time in seconds

Time= 18 months, which can be converted to "seconds" as;

18 months = [ 18 monthsx 30 days x 24 hours x 60 min x 60 sec] = 46656000

Then

time= 46656000 seconds

Power=2 watt

If we substitute into equation (1) we have

Energy = 2 watt × 46656000 seconds

Energy= 93312000 Joules

7 0

2 years ago

A mass of 100 kg is pulled by a 392 N force in the +X direction along a rough surface (uk=0.4) with uniform velocity v=20 m/s. W

alexdok [17]

Answer:

The total work done will be zero.

Explanation:

Given that,

Mass = 100 kg

Force = 392 N

Velocity = 20 m/s

Distance s= 10 m

We need to calculate the work done

Using balance equation

The net force will be

$F'=F-\mu mg$

$F'=392-0.4\times100\times9.8$

$F'=0$

The net force is zero.

Hence, The total work done will be zero by all forces on the object.

5 0

3 years ago

7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m

Nesterboy [21]

Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

$n=\frac{m }{M_m}$

where

$M_m = 18.02 g/mol$ is the molar mas

m = 10.0 g is the mass

Substituting

$n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol$

Now we know that the heat of fusion is

$H_{fus}=6.01 kJ/mol$

so the thermal energy needed to fuse the ice is

$Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ$

6 0

3 years ago

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