1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elodia [21]
4 years ago
8

Two parallel conductors carrying current in the same direction attract each other. If they are permitted to move toward each oth

er, the forces of attraction do work. From where does the energy come from? Does this contradict the assertion in the previous chapter that magnetic forces on moving charges do no work? Explain.
Physics
1 answer:
Tatiana [17]4 years ago
8 0

Answer:

Explanation:

The energy comes form the magnetic force acting on both the wires. As they attract each other so they travel some distance due to which work is there and this work is converted into energy.

You might be interested in
A wave with a large amplitude has a lot of             a.vibration  b.speed   c.energy    
adoni [48]
<span>A wave with a large amplitude has a lot of             a.vibration  b.speed  <u> c.energy</u></span>
6 0
3 years ago
Read 2 more answers
To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T
Fantom [35]

Answer:

V_1= 3.4*10^7m/s

Explanation:

From the question we are told that

Nucleus diameter d=5.50-fm

a 12C nucleus

Required kinetic energy K=2.30 MeV

Generally initial speed of proton must be determined,applying the law of conservation of energy we have

            K_2 +U_2=K_1+U_1

where

K_1 =initial kinetic energy

K_2 =final kinetic energy

U_1 =initial electric potential

U_2 =final electric potential

mathematically

   U_2 = \frac{Kq_pq_c}{r_2}

where

r_f=distance b/w charges

q_c=nucleus charge =6(1.6*10^-^1^9C)

K=constant

q_p=proton charge

Generally kinetic energy is know as

         K=\frac{1}{2}  mv^2

Therefore

         U_2 = \frac{Kq_pq_c}{r_2} + K_2=\frac{1}{2}  mv_1^2 +U_1

Generally equation for radius is d/2

Mathematically solving for radius of nucleus

         R=(\frac{5.50}{2}) (\frac{1*10^-^1^5m}{1fm})

         R=2.75*10^-^1^5m

Generally we can easily solving mathematically substitute into v_1

   q_p=6(1.6*10^-^1^9C)

   K_1=9.0*10^9 N-m^2/C^2

   U_1= 0

   R=2.75*10^-^1^5m

   K=2.30 MeV

   m= 1.67*10^-^2^7kg

   V_1= (\frac{2}{1.67*10^-^2^7kg})^1^/^2 (\frac{(9.0*10^9 N-m^2/C^2)*(6(1.6*10^-^1^9C)(1.6*10^-^1^9C)}{2.75*10^-^1^5m+2.30 MeV(\frac{1.6*10^-^1^3 J}{1 MeV}) }

    V_1= 3.4*10^7m/s

Therefore the proton must be fired out with a speed of V_1= 3.4*10^7m/s

8 0
3 years ago
Gaseous helium is in thermal equilibrium with liquid helium at 6.4 K. The mass of a helium atom is 6.65 × 10−27 kg and Boltzmann
chubhunter [2.5K]

Answer:

162.78 m/s is the most probable speed of a helium atom.

Explanation:

The most probable speed:

v_{mp}=\sqrt{\frac{2K_bT}{m}}

K_b= Boltzmann’s constant =1.38066\times 10^{-23} J/K

T = temperature of the gas

m = mass of the gas particle.

Given, m = 6.65\times 10^{-27} kg

T = 6.4 K

Substituting all the given values :

v_{mp}=\sqrt{\frac{2\times 1.38066\times 10^{-23} J/K\times 6.4 K}{6.65\times 10^{-27} kg}}

v_{mp}=162.78 m/s

162.78 m/s is the most probable speed of a helium atom.

4 0
4 years ago
Claudia throws a baseball to her dog. Which free-body diagram shows the
chubhunter [2.5K]

Answer:

only the weight of the ball will act on the ball

Explanation: There is no contact force on the ball. Also there is no air resistance on the ball so the friction force on the ball due to air is not shown

6 0
4 years ago
Which of the following properties of a mass-on-a-spring system undergoing simple harmonic motion can be changed without affectin
tamaranim1 [39]
<h2>Answer: Amplitude</h2>

If we are talking about simple harmonic motion, we are talking about waves and in this case the frequency f is related to the period of oscillation T in an inverse proportion.

Now, for a mass-on-a-spring system the period is given by:

T=2\pi\sqrt{\frac{m}{k}}

Where m is the oscillating mass and k the spring constant, which depends on the spring stillness.

As we can see in this equation:

If we change m and k we will affect the period, hence the frequency.

Nevertheless, we do not see any relation with the Amplitude, this means the period (hence the frequency) does not depend on the amplitude.

8 0
3 years ago
Other questions:
  • A 1.0-in.-diameter hole is drilled on the centerline of a long, flat steel bar that is 1 2 thick and 4 in. wide. The bar is subj
    11·2 answers
  • What is the main function of a telescope?
    15·2 answers
  • Granite is uplifted by the movement of tectonic plates. It will most likely become _____. igneous rock sedimentary rock metamorp
    6·1 answer
  • A 1750-kilogram cars travels at a constant speed of 15.0 meters per second around a horizontal, circular track with a radius of
    6·1 answer
  • What is the mass of .5 newtons(N)?
    15·1 answer
  • The study of charges in motion and their
    12·1 answer
  • A 95-kg astronaut is stranded from his space shuttle. He throws a 2-kg hammer away from the shuttle with a velocity of 19 m/s .
    11·1 answer
  • When you measure the mass of an object you are also measuring its what
    10·1 answer
  • Assume that Michael's teacher has a rule that if a student talks out-of-turn three times in one day, that student must stay in f
    9·1 answer
  • What is the energy (in evev) of a photon of visible light that has a wavelength of 500 nmnm?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!