We make use of the equation: v^2=v0^2+2a Δd. We substitute v^2 equals to zero since the final state is halting the truck. Hence we get the equation -<span>v0^2/2a = Δd. F = m a from the second law of motion. Rearranging, a = F/m
</span>F = μ Fn where the force to stop the truck is the force perpendicular or normal force multiplied by the static coefficient of friction. We substitute, -v0^2/2<span>μ Fn/m</span> = Δd. This is equal to
Answer:
-
Explanation:
We are given that
Mass of cars= m=1900 kg
Initial speed of car=u=20 m/s
Final speed of car=v=0
Time=
=1.3 s
We have to find the average force exerted on the car.
Average force=



Hence, the average force exerted on the car that hits a line of water barrels=-
B) All nonzero digits are significant.
The concept that we need here to give a proper solution is mutual inductance.
The mutual inductance is given by the expression

Where,
I = current
N = Number of turns
Flux through the solenoid.
Part A) Then we have in our values that,



Replacing in the equation,


Part B) Here is required the Flux, then using the same expression we have that

We conserve the same value for the Inductance but now we have a current of 2.6, then


Therefore the flux in Solenoid 1 is 