I will name block a as Ma=5 kg, block b as Mb=10 kg and mass of the pulley M=3 kg and radius as R. Since the system will accelerate in the direction of the block b because it has greater mass, I will take that direction as positive. Both blocks and the pulley have the same acceleration because the slipping on the pulley is neglected. First, the equations of motion:
Mb*g-Tg=MbαR and
Ta-Ma*g=MaαR,
where Ta and Tb are the tensions of the cord, g=9.81 m/s^2 and α is the angular accereration. Also a=αR where a is the acceleration of the system.
Now the equation of rotational dynamics of a solid body:
(Tb-Ta)R=Iα=(1/2)*M*R^2*α, where (1/2)*M*R^2 is the moment of inertia of a disc.
When we input Tb=Mb*g - Mb*α*R and Ta=Ma*g + Ma*α*R from the first two equations into the third we get: (Mb*g - Mb*α*R - Ma*α*R - Ma*g)*R=(1/2)*M*R^2*α.
We solve for α and get: α=(Mb*g-Ma*g)/((1/2)*MR+Mb*R+Ma*R)=2.97 rad/s^2.
We know that a=α*R and we easily get a=0.4455 m/s^2
Answer:
<h2>Newton Second low say" the acceleration of a body id directly proportional to the force acting on the body and inversly proportional to tje mass of the body "</h2>
Explanation:
Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it. ... Newton's second law is one of the most important in all of physics.
<h3>I Hope my answer is Helpfull thanks</h3>
There is no thing here I can answer so imma just say all of the above because I have no idea what else to say so thx for the points
Final velocity = Vf=0 <span>
Initial velocity = Vi = 9.5m/s
Acceleration = a = -4.6m/s</span>²<span>
Time = t =? </span>
Now use the formula;<span>
Vf=Vi+at
<span>0=9.5 - 4.6m/s</span></span>²t
<span>
-9.5 = -4.6m/s</span>²(t)
9.5/4.6 = t<span>
<span>T= 2.01s</span></span>
