Answer:
1. F = 45,458.17 N
2. P = 12,800,000 W
Explanation:
Part 1. The thrust force is the sum of the forces on the air and on the fuel.
For the air, 107 kg of air is accelerated from 281 m/s to 679 m/s in 1 second.
F = ma
F = (107 kg) (679 m/s − 281 m/s) / (1 s)
F = 42,586 N
For the fuel, 4.23 kg of fuel is accelerated from 0 m/s to 679 m/s in 1 second.
F = ma
F = (4.23 kg) (679 m/s − 0 m/s) / (1 s)
F = 2,872.17 N
So the thrust on the jet is:
F = 42,586 N + 2,872.17 N
F = 45,458.17 N
Rounded to three significant figures, the force is 45,500 N.
Part 2. Power = work / time, and work = force × distance, so:
Power = force × distance / time
Power = force × velocity
P = (45,458.17 N) (281 m/s)
P = 12,773,745.77 W
Rounded to three significant figures, the power is 12,800,000 W.
Answer:
somatosensory
Explanation:
The primary somatosensory cortex specializes in receiving signals from different parts of the body.
Answer:
The average speed of the bus, v = 1.55 m/s
Explanation:
Given that,
Number of blocks traveled by bus towards east = 6
Number of blocks traveled by bus towards north = 8
Length of each block = 100 m
Distance traveled by bus towards east 6 x 100 = 600 m
Distance traveled by bus towards north 8 x 100 = 800 m
The total distance traveled, d = 600 + 800 = 1400
Time taken by the bus to travel is, t = 15 minutes
The velocity is given by the formula
v = d/t m
Substituting the values in the above equation
v = 1400 m /(15 x 60) s
= 1.55 m/s
Hence, the average speed of the bus, v = 1.55 m/s
Answer:
Explanation:
Given that,
Number of turns of coil
N = 50 turns
Initial area of plane
A1 = 0.18 m²
The coil it stretch to a no area in time t = 0.1s
No area implies that the final area is 0, A2 = 0 m²
Constant magnetic field strength
B = 1.51 T
EMF?
EMF is given as
Using far away Lenz law
ε = —N• dΦ/dt
Where Φ = BA
Then,
ε = —N• d(BA)/dt
Since B is constant,
ε = —N•B dA/dt
ε = —N•B (∆A/∆t)
ε = —N•B(A2—A1)/(t2-t1)
ε = —50 × 1.51 (0—0.18)/(0.1—0)
ε =—75.5 × —0.18 / 0.1
ε = 135.9 V
The induced EMF is 135.9V
Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.
Since the area lines in the plane, then the induced emf will be out of the page
