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Bas_tet [7]
3 years ago
14

Which would be best categorized as heat transfer by conduction?a)wearing a white shirt to stay cool on a summer day.b)cooling a

burn on your hand by running your hand under cold water.c)feeling the heat from a light bulb with your hand when touching the bulb.d)feeling the heat from a light bulb while holding your hand from 6 inches away?
Physics
2 answers:
Bezzdna [24]3 years ago
7 0

Answer:

C.Feeling the heat from a light bulb with your hand when touching the bulb.

Explanation:

Marina CMI [18]3 years ago
7 0

Answer:  Feeling the heat from a light bulb with your hand when touching the bulb.

Explanation: Feeling the heat from a light bulb with your hand when touching the bulb. Conduction - molecules touch each other or bump into each other. There must be contact!

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There are two atoms of potassium bonded to one atom of sulfur.
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3 years ago
Suppose a proton ( = 1. 67×10^−27 kg) is confined to a box of width = 1. 00×10^−14 m (a typical nuclear radius).
dimulka [17.4K]

Answer:

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Explanation:

3 0
3 years ago
A scaffold of mass 57 kg and length 6.5 m is supported in a horizontal position by a vertical cable at each end. A window washer
Mrac [35]

Explanation:

The given data is as follows.

     m_{1} = 57 kg,        m_{2} = 79 kg

      l_{1} = 6.5 m,         l_{2} = (6.5 - 1.9) m = 4.6 m

(a)  The sum of torque ends about far end is as follows.

    m_{1}g \frac{l_{1}}{2} + m_{2}g \times l_{2} - T \times l_{1} = 0

     57 \times 9.81 \times \frac{6.5}{2} + 79 \times 9.81 \times (6.5 - 1.9) - T \times 6.5 = 0

                     T = 828 N

Therefore, 828 N is the tension in the cable closer to the painter.

(b)  Now, we will calculate the sum about close ends as follows.

m_{1}g \frac{l_{1}}{2} + m_{2}g \times (1.9) - T \times l_{1}    

  57 \times 9.81 \times \frac{6.5}{2} + 79 \times 9.81 \times (1.9) - T \times 6.5 = 0

                            T= 506 N

Therefore, 506 N is the tension in the cable further from the painter.  

8 0
3 years ago
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb
kramer

Answer:

12552 J or 3000 calories

Explanation:

Q = m × c × ∆T

Where;

Q = amount of heat energy (J)

m = mass of water (g)

c = specific heat capacity (4.184 J/g°C)

∆T = change in temperature

For 50mL of water, there are 50g, hence, m = 50g, c = 4.184 J/g°C, initial temperature = 0°C, final temperature = 60°C.

Q = m × c × ∆T

Q = 50 × 4.184 × (60 - 0)

Q = 209.2 × 60

Q = 12552 J

Hence, the amount of heat energy used to heat the water is 12552 J or 3000 calories

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3 years ago
Which of these best defines power?
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Answer:

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Explanation:

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