Question

What mass of carbon dioxide occupies a volume of 81.3 L at 204 kPa and temperature of 95.0 C

Answer 1

The mass of CO₂ present is 238.52g

Explanation:

Given:

Volume, V = 81.3 L

Pressure, P = 204 kPa = 204000 Pa

Temperature, T = 95°C

                       T = 95 + 273 K

                       T = 368 K

Mass of CO₂, x = ?

Molecular weight of CO₂ = 44 g/mol

According to gas law:

PV = nRT

where,

n = number of moles

n = given mass/ molecular mass

R = gas constant

R = 8.314 X 10³ L Pa K⁻¹ mol⁻¹

Substituting the value:

$204000 X 81.3 = \frac{x}{44} X 8.314 X 10^3 X 368\\ \\x = \frac{44 X 204 X 81.3}{8.314 X 368} \\\\x = 238.52 g$

Therefore, the mass of CO₂ present is 238.52g