Answer:
2NaOH + H2So4 》Na2So4+ 2H2O
Explanation:
SODIUM HYDROXIDE, 2NaOH IS (aq)
FULFURIC ACID, H2So4 IS (aq)
SODIUM SULFATE, Na2So4 IS (aq)
WATER,2H20 IS (l)
The true statements are B, C, and D
-first ( A ) the concentrations of reactants and products are equal is false, As the concentrations of reactants and products may be different from each other.
- But (B) the concentrations of reactants and product remains constant is true, as the equilibrium remains when there is no change in the concentration of the reactants and products.
-(c) reactants are being converted to products (and vise verse) is true also, as there are reactions still happened at a constant rate so it looks like nothing is happening.
Answer:-
2.0 L
Explanation:-
Initial Volume = V 1 = 3.0 L
Initial Pressure P 1 = 4.0 atm
New pressure P 2 = 6.0 atm
Using boyle's law
P1 V1 = P2 V2
New Volume V2 = P1 V1 / P2
= 4.0 atm x 3.0 L / 6.0 atm
= 2 .0 L
Answer:
n = 5 to n = 6 absorption
n = 9 to n = 6 emission
n = 6 to n = 4 emission
n = 6 to n = 7 absorption
Explanation:
According to the Bohr's model of the atom. An electron in an atom may absorb energy and move from a lower energy level to a higher energy level. This requires absorption of energy that is equal to the energy difference between the two levels.
Similarly, an electron may move from a higher to a lower energy level, releasing energy that is equal to the energy difference between the higher and the lower level. This is known as emission.
Hence, if the electron is moving from a lower energy level to a higher energy level, an absorption has taken place, e.g n = 5 to n = 6
When an electron moves from a higher energy level to a lower energy level, an emission has taken place e.g n = 9 to n = 6
The answer is C) catalyst speed up reactions and activation energy
