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iragen [17]
2 years ago
10

Identify and explain one way in which we try to deal with infiltration? What are the benefits and cost of that particular soluti

on?
Physics
1 answer:
tigry1 [53]2 years ago
5 0

Answer:

i vigilate

Explanation:

You might be interested in
. Determine if approximate cylindrical symmetry holds for the following situations. State why or why not. (a) A 300-cm long copp
MA_775_DIABLO [31]

Answer:

a) Yes

b) No

Explanation:

In the first case, part a, yes we can say for certainty that cylinderical symmetry holds. Why so? You may ask. This is because from the question, we are told that the length of the rod is 300 cm. And this said length is longer than the distance to the point from the center of the rod, which is 5 cm.

In the second half of the question, I beg to disagree that cylindrical symmetry holds. Again, you may ask why, this is because the length of the rod in this case, is having the same order of magnitude as the distance to the center of the rod. Thus, it is not symmetrical.

6 0
3 years ago
A short-wave radio antenna is supported by two guy wires, 155 ft and 175 ft long. Each wire is attached to the top of the antenn
Vladimir79 [104]

Answer:

163.8 ft

Explanation:

In triangle ABD

AB = 155 ft

Cos63 = \frac{BD}{AB} = \frac{BD}{155}\\BD = 155 Cos63 \\BD = 70.4 ft

Sin63 = \frac{AD}{AB} = \frac{AD}{155} \\AD = 166 Sin63\\AD = 148 ft

Using Pythagorean theorem in triangle ADC

AC^{2} = AD^{2} + DC^{2} \\175^{2} = 148^{2} + DC^{2} \\DC = 93.4 ft

d = distance between the anchor points

distance between the anchor points is given as

d = BD + CD = 70.4 + 93.4\\d = 163.8 ft

5 0
3 years ago
Read 2 more answers
Can anyone help me with these questions? TIA!<br> (Don’t actually answer please! :) )
nataly862011 [7]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Question 7: </h2>

 \huge\text{Graphs:}

The graph of  

• The I-V for Ohmic Metal wire conductor at constant temperature  always shows a straight line between the Current(I) plotted at Y axis and Voltage(V) plotted at X axis. Picture 1

• The I-V graph for Diode shows that first the current is zero but as we increase the potential difference(voltage), it results in the increase in the current. Picture 2

<h2>_____________________________________ </h2><h2>Question 8: </h2>

\Large\textbf{Diode:}  

A diode is a device that allows current to flow in only one direction.

\Large\textbf{Forward and Reverse Biasing:}  

Forward Bias, When a diode is forward bias (a voltage in the "forward" direction) then the P-side of the diode is attached to the positive terminal and N-side is fixed to the negative side of the battery which is connected, current flows freely through the device. The forward bias decreases the thickness of potential barrier(The potential barrier barrier in which the charge requires additional force for crossing the region)

Reverse Bias, When a diode is Reverse bias(a voltage in the "backward direction) then the P-side of the diode is connected to the negative terminal and N-side is connected to the positive terminal of the battery which is connected. The reverse bias increases the thickness of the potential barrier resulting in the flow of no current.

 \Large\textbf{Answer to the Question "Resistance"}

The Forward bias decreases the resistance of the diode whereas the reversed bias increases the resistance of the diode. As in forward biasing the current is easily flowing through the circuit whereas reverse bias does not allow the current to flow through it.

<h2>_____________________________________ </h2><h2>Best Regards, </h2><h2>'Borz' </h2>

8 0
3 years ago
Which of the following are required for scientific questions
icang [17]
The answer is D-Testable

Hope this helps
6 0
3 years ago
Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generate
tigry1 [53]

Explanation:

It is given that,

Average power per unit mass generated by Lance, \dfrac{P}{m}=6.5\ W/kg

P=6.5\times 75=487.5\ W

(a) Distance to cover race, d = 160\ km =160\times 10^3\ m

Average speed of the person, v = 11 m/s

If t is the time taken to cover the race.

t=\dfrac{d}{v}

t=\dfrac{160\times 10^3\ m}{11\ m/s}

t = 14545.46 s

Let W is the work done. The relation between the work done and the power is given by :

P=\dfrac{W}{t}

W=P\times t

W=487.5\times 14545.46

W = 7090911.75 J

(b) Since, 1\ J=2.389\times 10^{-4}\ calories

So, in 7090911.75 J, W=7090911.75 \times 2.389\times 10^{-4}

W = 1694.01 J

Hence, this is the required solution.

6 0
3 years ago
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