At the "very top" of the ball's path, there's a tiny instant when the ball
is changing from "going up" to "going down". At that exact tiny instant,
its vertical speed is zero.
You can't go from "rising" to "falling" without passing through "zero vertical
speed", at least for an instant. It makes sense, and it feels right, but that's
not good enough in real Math. There's a big, serious, important formal law
in Calculus that says it. I think Newton may have been the one to prove it,
and it's named for him.
By the way ... it doesn't matter what the football's launch angle was,
or how hard it was kicked, or what its speed was off the punter's toe,
or how high it went, or what color it is, or who it belongs to, or even
whether it's full to the correct regulation air pressure. Its vertical speed
is still zero at the very top of its path, as it's turning around and starting
to fall.
Ohm’s Law states that electrical current is proportional to voltage and therefore inversely proportional to resistance - V = I x R
Answer:
Explanation:
Given that
T₁ = 290 K
P₁ = 100 KPa
Power P =5.5 KW
mass flow rate
Lets take the exit temperature = T₂
We know that
If we assume that process inside the compressor is adiabatic then we can say that
That is why the exit pressure will be 4091 KPa.
Increase because kinetic energy is all about the speed of an object and the more speed the more kinetic energy.
The book Two New Sciences is the book that would later influence Sir Isaac Newton
