Answer:

Explanation:
given,
op-amp circuit with a gain of = (Av₁) = 96 V/V
Band width = (Bw₁) = 8 kHz
Required bandwidth(Bw₂) = 32 kHz
Highest gain available =(Av₂) = ?
For the given system Bandwidth product is constant
Av₁ Bw₁ = Av₂ Bw₂
96 x 8 = Av₂ x 32


the highest gain available under these conditions 
The best answer is that it reduces the level of ground water
Answer:
Explanation:
Magnetic field near current carrying wire
= 
i is current , r is distance from wire
B = 10⁻⁷ x 
force on second wire per unit length
B I L , I is current in second wire , L is length of wire
= 10⁻⁷ x
x 33 x 1
= 3234 x 
This should balance weight of second wire per unit length
3234 x
= .075
r =
x 10⁻⁷
= .0043 m
= .43 cm .