Answer:
20.88 m/s
Explanation:
Curve A:
theta = 12.7, vA = 19.1 m/s
Curve B:
Theta = 15.1 degree
Let the speed is v.
By the use of given formula
tanθ = v^2 / rg
For Curve A
tan 12.7 = (19.1)^2 / r g ...... (1)
For Curve B
tan 15.1 = v^2 / r g ......(2)
Divide equation (2) by equation (1), we get
tan 15.1 / tan 12.7 = v^2 / (19.1)^2
0.269 / 0.225 = v^2 / 364.81
v = 20.88 m/s
Answer:
The correct choice is 8o.
Explanation:
The given weight is hanging at the mid point of the rope and the buildings are at the same level, Obtain the given equation by equating the vertical components of force,
2Tsin(φ)=W
where φ is the angle made by rope with the horizontal.
Given T=1800 N and W=500 N, the value of φ is calculated as follows,
2*1800*sin(φ)=500
sin(φ)=0.1388
φ=7.90
φ≈8o
Check out similar questions.
brainly.com/question/13735944
#SPJ10
Answer:
r = 0.728 m
Explanation:
The intensity is defined as the ratio between the power per unit area
I = P / A
Where A is the area of the sphere where the wave is
A = 4π r²
In this exercise we are given the power of the P = 10.0 W micro waves, the safe intensity I₁ = 1.5 W / m²
A₁ = P / I₁
Calculate
A₁ = 10.0 / 1.5
A₁ = 6.6667 m²
Let's clear the radius of the sphere
r = √ A / 4π
r = √ (6.6667 / 4π)
r = 0.728 m
By uncertainty principle
λ = h / p.
Where λ = wavelength, h = Planck's constant = 6.63 * 10⁻³⁴ Js
λ = wavelength = 550 nm = 550 * 10⁻⁹ m, Mass of electron = 9.1 * 10 ⁻³¹ kg
p = Momentum = mv
λ = h / mv
v = h / mλ
v = 6.63 * 10⁻³⁴ / (9.1 * 10⁻³¹ * 550 * 10⁻⁹)
v = 1 324 675.325 m/s
v ≈ 1.325 *10⁶ m/s
Answer:
294.3 N
Explanation:
In this situation, we are told that the crate is not accelerating in the horizontal plane. But also it is not accelerating in the vertical plane. Meaning that the sum of all vertical forces add up to zero.
Fnet = ma
Weight + Normal force = mass * acceleration
-(30 kg * 9.81 m/s²) + Normal force = 30.0 kg * 0 m/s²
Normal force = 294.3 N
