Ask question

Ask question

All categories

3 years ago

8

A circular surface with a radius of 0.057 m is exposed to a uniform external electric field of magnitude 1.44 × 104 N/C. The mag

nitude of the electric flux through the surface is 78 N · m2/C. What is the angle (less than 90) between the direction of the electric field and thenormal to the surface?

1 answer:

klio [65]3 years ago

4 0

Answer:

57.94°

Explanation:

we know that the expression of flux

$\Phi =E\times S\times COS\Theta$

where Ф= flux

E= electric field

S= surface area

θ = angle between the direction of electric field and normal to the surface.

we have Given Ф= 78 $\frac{Nm^{2}}{sec}$

E= $1.44\times 10^{4}\frac{Nm}{C}$

S= $\pi \times 0.057^{2}$

$COS\Theta =\frac{\Phi }{S\times E}$

= $\frac{78}{1.44\times 10^{4}\times \pi \times 0.057^{2}}$

=0.5306

θ=57.94°

You might be interested in

After giving an intense performance, a confused and disoriented ﬂautist has wandered onto the motorway! They are playing a con

leva [86]

This is a Doppler effect. Generally, if you move to a frequency source, you would detect an increase in frequency and when you move away from a source you would detect a decrease.

For this question, before you pass them, you are actually approaching them, so you would hear a higher frequency than the constant 300 Hz they are playing at.

Using the condensed formula:

f ' = ((v <u>+</u> vd)/(v <u>+</u> vs)) * f

Where: vd = Velocity of the detector.
   vs = Velocity of the frequency source.
   v = Velocity of sound in air.
   f ' = Apparent frequency.
   f = Frequency of source.

v = 343 m/s, vd = detector = 27.8 m/s, vs = velocity of the source =0. (the flautists are not moving).
f = 300 Hz.

There would be an overall increase in frequency, so we maintain a plus at the numerator and a minus at the denominator.

f ' = ((v + vd)/(v - vs)) * f

f ' = ((343+ 27.8)/(343 - 0)) * 300
   = (370.8/343)* 300 = 324.3

Therefore frequency before passing them = 324.3 Hz.

Cheers.

4 0

3 years ago

Which of the following is a form of kinetic energy?

aalyn [17]

Answer:

A) Sound Energy

Explanation:

Electrical and nuclear energy are examples of potential energy

6 0

4 years ago

Read 2 more answers

German physicist Werner Heisenberg related the uncertainty of an object's position ( Δ x ) to the uncertainty in its velocity (

Ierofanga [76]

Answer:

The uncertainty in the position of the electron is $5.79x10^{-9}m$

Explanation:

The Heisenberg uncertainty principle is defined as:

$\Lambda p\Lambda x$ ≥ $\frac{h}{4 \pi}$ (1)

Where $\Lambda p$ is the uncertainty in momentum, $\Lambda x$ is the uncertainty in position and h is the Planck's constant.

The momentum is defined as:

$p =mv$ (2)

Therefore, equation 2 can be replaced in equation 1

$\Lambda (mv) \Lambda x$ ≥ $\frac{h}{4 \pi}$

Since, the mass of the electron is constant, v will be the one with an associated uncertainty.

$m \Lambda v \Lambda x$ ≥ $\frac{h}{4 \pi}$ (3)

Then, $\Lambda x$ can be isolated from equation 3

$\Lambda x$ ≥ $\frac{h}{m \Lambda v 4 \pi}$ (4)

$\Lambda x = \frac{6.626x10^{-34}J.s}{(9.11x10^{-31} kg)(0.01x10^{6}m/s) 4 \pi}$

But $1J = Kg.m^{2}/s^{2}$

$\Lambda x = \frac{(6.624x10^{-34} Kg.m^{2}/s^{2}.s)}{(9.11x10^{-31} kg)(0.01x10^{6}m/s) (4 \pi)}$

$\Lambda x = 5.79x10^{-9}m$

Hence, the uncertainty in the position of the electron is $5.79x10^{-9}m$

7 0

3 years ago

A cyclist moving with a constant velocity of 6.0 m/s forward passes a car that is just starting. If the car has a constant accel

sergiy2304 [10]

After 6 seconds, the car will surpass the cyclist.

<h3><u>Explanation:</u></h3>

The speed of the cyclist = 6 m/s.

Let after time t sec, the car will overtake the cyclist.

So, distance covered by the cyclist in t sec = 6t m

Initial velocity of the car is 0 m/s, because the car is just starting.

Acceleration of the car = $2 m/s^2$ .

Final velocity of the car =6 m/s.

So to cover the distance 6t, the time required by the car = $\frac{1}{2} \times a \times t^2 = \frac{1}{2} \times 2 \times t^2$

$6t = \frac{1}{2} \times 2 \times t^2\\6t = t^2$

t =6 sec

So, after 6 seconds, the car will surpass the cycle.

6 0

3 years ago

PLEASE HELP I NEED THIS DONE BY 11:59!<br> After how long do the cars pass each other???

ivann1987 [24]

Answer:

They pass after roughly 5 hours and 35 minutes.

3 0

3 years ago

Read 2 more answers