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3 years ago

Which converts mechanical energy to electrical energy?

Physics

1 answer:

LiRa [457]3 years ago

6 0

Answer:

c. A Generator

Explanation:

The whole point of a generator is to produce electrical energy. The generator will use a mechanical motor usually running off of gas to produce electricity.

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Imagine you want to create a model of Solar system (and beyond) with the Sun

kondaur [170]

Using the scale model of the Sun given;

The diameter of the Milky Way = 4.28 × 10¹¹ m
The diameter of the Earth = 5.44 × 10⁻³ m

<h3>What is the diameter of the Milky Way?</h3>

The diameter of the Milky Way is about 1 × 10¹⁸ km.

The diameter of the Sun is about 1.4 × 10⁶ km

The diameter of the Earth is about 1.27 × 10⁴ km.

Using the scale model of the Sun given, the diameter of the Milky Way = (1 × 10¹⁸ km/1.4 × 10⁶ km) × 0.6 m

The diameter of the Milky Way = 4.28 × 10¹¹ m

Using the scale model of the Sun given, the diameter of the Milky Way = (1.27 × 10⁴ km/1.4 × 10⁶ km) × 0.6 m

The diameter of the Earth = 5.44 × 10⁻³ m

In conclusion, the diameter of the Milky Way is far bigger than the Sun while the diameter of the Sun is about 5400 times bigger than the Earth.

Learn more about the Milky Way, Sun, and Earth at: brainly.com/question/1995133

#SPJ1

5 0

2 years ago

You drop a stone down off a bridge. You are able to count to 4.0 seconds when it finally hits the water. How high is the bridge?

mart [117]

Answer:

The height of the bridge is 78.4 m.

Explanation:

Given;

time of the stone motion off the bridge, t = 4.0 s

acceleration due to gravity, g = 9.8 m/s²

The height of the bridge is given by;

h = ut + ¹/₂gt²

where;

u is the initial velocity of the stone, u = 0

h = ¹/₂gt²

h = ¹/₂(9.8)(4)²

h = 78.4 m

Therefore, the height of the bridge is 78.4 m.

7 0

3 years ago

A car leaves an intersection traveling west. Its position 4 sec later is 21 ft from the intersection. At the same time, another

Alex_Xolod [135]

Answer:

15.8 ft/s

Explanation:

$\frac{da}{dt}$ = Velocity of car A = 9 ft/s

a = Distance car A travels = 21 ft

$\frac{db}{dt}$ = Velocity of car B = 13 ft/s

b = Distance car B travels = ft

c = Distance between A and B after 4 seconds = √(a²+b²) = √(21²+28²) = √1225 ft

From Pythagoras theorem

a²+b² = c²

Now, differentiating with respect to time

$2a\frac{da}{dt}+2b\frac{db}{dt}=2c\frac{dc}{dt}\\\Rightarrow a\frac{da}{dt}+b\frac{db}{dt}=c\frac{dc}{dt}\\\Rightarrow \frac{dc}{dt}=\frac{a\frac{da}{dt}+b\frac{db}{dt}}{c}\\\Rightarrow \frac{dc}{dt}=\frac{21\times 9+28\times 13}{\sqrt{1225}}\\\Rightarrow \frac{dc}{dt}=15.8\ ft/s$