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zloy xaker [14]
3 years ago
7

Which gas law can you use to solve for moles of gas

Chemistry
2 answers:
zubka84 [21]3 years ago
8 0

Answer:

gas law known as Avagadro's law is your answer

Sergio [31]3 years ago
4 0

Answer:

it would be the ideal gas law also known as Avagadro's law

Explanation:

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There are 1.204 x 10^24 atoms of oxygen. How many moles is this?
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Answer:

7.25 x 10^47

Explanation:

1.204 x 10^24 moles*6.022 x 10^23 avogadro's number= 7.25 x 10^

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Ions stick together with<br> A . Covalent bonds <br> B. Negative bonds<br> C. Ionic bonds
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A certain water tower hold 4.6×10^5 gallons of water. find the volume of that water in liters.​
Readme [11.4K]

Answer: 1741289L

Explanation:

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6 0
3 years ago
Read 2 more answers
A chemist uses hot hydrogen gas to convert chromium(III) oxide to
Darya [45]

Answer: 3.024 g grams of hydrogen are needed to  convert 76 grams of chromium(III) oxide, Cr_{2}O_{3}

Explanation:

The reaction equation for given reaction is as follows.

Cr_{2}O_{3} + 3H_{2} \rightarrow 2Cr + 3H_{2}O

Here, 1 mole of Cr_{2}O_{3} reacts with 3 moles of H_{2}.

As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide (Cr_{2}O_{3}) is 152 g/mol.

Number of moles is the mass of substance divided by its molar mass. So, moles of Cr_{2}O_{3} is calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{76 g}{152 g/mol}\\= 0.5 mol

Now, moles of H_{2}.given by 0.5 mol of Cr_{2}O_{3} is calculated as follows.

0.5 mol Cr_{2}O_{3} \times \frac{3 mol H_{2}}{1 mol Cr_{2}O_{3}}\\= 1.5 mol H_{2}

As molar mass of H_{2} is 2.016 g/mol. Therefore, mass of H_{2} is calculated as follows.

No. of moles = \frac{mass}{molar mass}\\1.5 mol = \frac{mass}{2.016 g/mol}\\mass = 3.024 g

Thus, we can conclude that 3.024 g grams of hydrogen are needed to  convert 76 grams of chromium(III) oxide, Cr_{2}O_{3}.

7 0
3 years ago
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