Answer:
There are four electronsin a beryllium atom. The four set of quantum numbers for the ground-state beryllium atom are:
- n = 1, ℓ = 0, mℓ = 0, ms = +1/2
- n = 1, ℓ = 0, and mℓ = , ms = -1/2
- n = 2, ℓ = 0, mℓ = 0, ms = +1/2
- n = 2, ℓ = 0, and mℓ = , ms = -1/2
Explanation:
<em>Be</em> is the chemical symbol for beryllium.
The atomic number of beryllium is 4.
Hence, beryllium atoms have 4 protons and 4 electrons.
The electron configuration for the ground-state Be atom, is:
So, you have to find the sets of quantum numbers for the two 1s and the two 2 s electrons.
<u>For the two 1s electrons</u>:
- <u>Principal quantun number, n</u>.
The principal quantum number, n, is the main energy level and is indicated by the number in front of the letter (kind of orbital).
So, for the two 1s electrons, n = 1
- <u>Orbital Angular Momentum Quantum Number, ℓ</u>
The angular moment quantum number, ℓ, is the shape of the orbital.
The possible numbers for ℓ are from 0 to n- 1. Orbital s means ℓ = 0.
- <u>Magnetic Quantum Number, mℓ</u>
The magnetic quantum number, mℓ, represents the space orientation of the orbital.
The possible numbers for mℓ are from - ℓ to + ℓ. Hence, for the two `s electrons mℓ is 0.
So far you have: n = 1, ℓ = 0, and mℓ = 0.
- <u>Spin quantum number, s or ms</u>
The spin quantum number, related to the rotation of the electron, may be only +1/2 or -1/2.
So, now you have the two sets for these two electrons:
- n = 1, ℓ = 0, mℓ = 0, ms = +1/2
- n = 1, ℓ = 0, and mℓ = , ms = -1/2
<u>For the two 2s electrons:</u>
- ℓ = 0 (because the orbital is 2)
So, the two sets for the two s electrons are:
- n = 2, ℓ = 0, mℓ = 0, ms = +1/2
- n = 2, ℓ = 0, and mℓ = , ms = -1/2