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Yakvenalex [24]
3 years ago
12

In 1980, approximately 6 million women were enrolled in college in the United States. The number of women who enroll in college

has increased at a rate of 0.14 million women per year. At the same time, there were about 5.4 million men enrolled in college in 1980 and that number increased at a rate of 0.08 million men per year. In what year was enrollment at the men's college and women's college equal?

Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0

Answer:

According to Matthewson, “then percent of collage students will graduate witching four years of beginning college.”

I just took the quiz

Step-by-step explanation:

Mark brianliset please haha

Igoryamba3 years ago
6 0
Hiya!

First, you can plot this using a table. One side can be 'Women' and the other 'Men'. One the vertical side of it, write '1980', '1981', '1982', etc., for maybe fifteen years to be on the safe side. Then, your starting value is 6 million and 5.4 million, respectively.

Finally, start adding up! It will be, 6.14 million, 6.28 million, etc., and 5.4 million, 5.48 million, etc.

Once you're done, you can circle the year both were the same, and you can even plot this on a graph to prove to your teacher you know what's business! ;)

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one! :)
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Please help thank you.
marusya05 [52]
This problem can be completed in 2 ways. Both are acceptable.

Option 1:


This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.

The area of the rectangle is the base times the height.

9 \times 4=36

The area of one of the triangles is half the base times the height.

\dfrac{1}{2} \times 5 \times 4 = 10

The other triangle must have that area too.

36+10+10=56

The area is 56 square centimeters.

Option 2:

We can use the area formula for the trapezoid.

A=\dfrac{b_1+b_2}{2} \times h

Where b_1 is the length of the shorter base
and b_2 is the length of the longer base
and h is the height.

The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.

The height is 4.

A=\dfrac{9+19}{2} \times 4

=56

Same answer. The area is 56 square centimeters.

Both options are two acceptable ways the problem can be tackled.
7 0
3 years ago
Find the distance between A (6, -1) and B ( -18, 15)
timama [110]

Answer:

8√13 units

Step-by-step explanation:

We use the distance formula.

The distance formula states that the distance between two points (x, y) and (a, b) is equal to:

d = \sqrt{(x-a)^2+(y-b)^2}

Here, x = 6, y = -1, a = -18, and b = 15. Plug these in:

d = \sqrt{(x-a)^2+(y-b)^2}

d = \sqrt{(6-(-18))^2+(-1-15)^2}=\sqrt{24^2+(-16)^2} =\sqrt{576 + 256} =\sqrt{832} = 8√13

The answer is thus 8√13 units.

<em>~ an aesthetics lover</em>

7 0
3 years ago
Read 2 more answers
Rayshawn has a certain amount of money if he spends $20 then he has 1/3 of the original amount how much money did Rayshawn have
erik [133]

Answer:

Rayshawn originally had $30.

Step-by-step explanation:

i) Rayshawn has a certain amount of money. Let us say this amount is $x.

ii) Rayshawn spends $20 which means that he is left with $(x - 20)

iii) it is also given that amount of money left after spending $20 is \dfrac{1}{3} of the original amount, $x, the amount remaining is \dfrac{\$x}{3}.

iv) from the information given in ii) and iii) we get

     $(x - 20) = \dfrac{\$x}{3},  Therefore we get 3x - 60 = x , therefore 2x = 60,

  Therefore x = $30. Rayshawn originally had $30.

7 0
3 years ago
Mr. Tragrr has $500.00 to spend at a bicycle store. All the prices listed down below include tax.
fgiga [73]

To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.

Spent so far:

... 273.98 + 3×7.23 +42.36 = 338.03

Remaining available funds:

... 500.00 -338.03 = 161.97

The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.

Mr. Traeger can buy two (2) cycling outfits with the remaining money.

_____

The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.

8 0
3 years ago
Read 2 more answers
A map of a rectangular park has a length of 4 inches and a width olo and a width of 6 inches. It uses a scale of 1 inch for ever
Zielflug [23.3K]

Answer:

The actual area of the park is 21,600 miles square.

Step-by-step explanation:

<u>Step 1: Calculate the area of the park</u>

<em>Area of rectangle = Length x width</em>

Length = 4 inches

Width = 6 inches

Scale factor is given as, 1 inch = 30 miles.

So, converting the length and width in miles by using the scale factor, we get

Length = 4 * 30 = 120 miles

Width =  6 * 30 = 180 miles

The formula of finding the area of an rectangle is:

<em>Area = length x width</em>

By putting the values in equation, we get

Area = 120 x 180

Area = 21,600 miles square

Therefore, the actual area of the park is 21,600 miles square.

8 0
3 years ago
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