The magnitude of the electric field at point a will be 13000 N/C towards .
Answer: Option C
Explanation:
We know,
The distance between and point a = 0.3 m
The distance between and point a = 0.2 m
Now,
The electric field on point a due to charge,
Where,
= 30 nC
r = 0.3 m
The electric field on point a due to charge,
Where,
= 45 n C
r’ = 0.2 m
To find the total electric field exerted on point a due to both of the charges, we need to add and . Thus, the net electric field of point a,
Now, putting all the values, we get;
Hence, the answer will be 13000 N/C directed to