$using \: the \: formula \\ t = \frac{2u \sin( \alpha ) }{g} where \: u = initial \: speed \: \\ \alpha = angle \: of \: projection \\ g = acceleration \: due \: to \: gravity \\ \frac{2 \times 50 \times \sin(30) }{10} \\ \frac{100 \times 0.5}{10} = \frac{50}{10} = 5seconds$

Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
2165/10=216.5metres

3 0

2 years ago

Emilio pushes a 100 kg freshman with 200 N of force. How much is the freshman accelerated?

ladessa [460]

Explanation:

F = MA

200 = 100 * A

A = 200/100

A = 2m/sec^2

<h3>hope it helps you </h3>

8 0

2 years ago

A substance freezes at -58c therefore substance melts at ?

Yanka [14]

The freezing point is the same as the melting point.

If it freezes at -58°C, hence the melting point is also -58°C.

3 0

2 years ago