When the reaction equation is:
HF ↔ H+ + F-
and when the Ka expression
= concentration of products/concentration of reactions
so, Ka = [H+][F-]/[HF]
when we assume:
[H+] = [F-] = X
and [HF] = 0.35 - X
So, by substitution:
6.8 x 10^-4 = X^2 / (0.35 - X) by solving for X
∴ X = 0.015 M
∴[H+] = X = 0.015
when PH = -㏒[H+]
∴PH = -㏒0.015
= 1.8
Answer:
John Dalton
Explanation:
John Dalton in 1808 suggested that all matter consists of tiny particles called atoms and that the atoms of a specific element are identical.
He postulated the Dalton's atomic theory which has the following important parts;
- All matters consists of indivisible particles called atoms
- Atoms of the same element are similar and are different from atoms of other elements.
- Atoms can neither be created nor destroyed.
- Atoms combine in simple whole ratios to form compounds.
Ionic bonds are formed when a cation and an anion transfer electrons. The anion gains electrons from the cation to finish its shell, and is usually a nonmetal or a metalloid. A cation gives the anion its electrons to get rid of its partial shell. Cations are metals.
Answer: Object B will heat up more.
Explanation:
The formula for specific heat is as follows.
Q = 
Where,
Q = heat provided
m = mass
C = specific heat
= change in temperature
Now, both the objects have same mass and equal amount of heat is applied.
According to the formula, the equation will be as follows.
= 
= 
Cancel m from both sides, as mass is same. Therefore,
= 
Cancel out the initial temperature and put the values of specific heat, then the equation will be as follows.
= 
Therefore, from the above equation it can be concluded that the object with low specific heat will heat up more as its specific heat will be inversely proportional to its final temperature.
Hence, object B will heat up more.
486 kPa will be the pressure of gas at 27 degrees.
Explanation:
Data given :
Initial pressure of the gas P1 = 810 kPa
initial temperature of the gas T1 = 227 degrees OR 500.15 K
final pressure of the gas =?
final temperature of the gas = 27 degrees OR 300.15 K
Gay Lussac's law is used to calculate the pressure of the gas at 27 degrees or 300.15 K
= 
P2 = 
Putting the values in the equation:
P2 = 
P2 = 486 KPa
486 Kpa is the pressure of the gas when temperature was reduced to 27 degrees.