When you transferred the hot metal from the boiling water and into the calorimeter, The effect will be
- Change in temp is positive
- Temp of metal V, dT=-ve
- No change occurs in the specific heat of metal
This is further explained below.
<h3>What is the Specific heat of the metal?</h3>
a )Since the metal of the cup is hot and the water inside is cold, the water's temperature will rise as heat is transferred from the metal to the liquid.
Change in temp is positive
b)
Due to (a), heat is lost from the food to the water in the cup, lowering the metal's temperature.
Temp of metal V, dT=-ve
c)
No change occurs in the specific heat of metal because of its constant property.
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Shale actually forms in the part of the rock cycle called compaction.
Answer: The molar enthalpy change is 73.04 kJ/mol
Explanation:
moles of HCl= 
As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.
volume of water = 100.0 ml + 50.0 ml = 150.0 ml
density of water = 1.0 g/ml
mass of water = 
q = heat released
m = mass = 150.0 g
c = specific heat = 
= change in temperature = 
Thus 0.0415 mol of HCl produces heat = 3031.3 J
1 mol of HCL produces heat = 
Thus molar enthalpy change is 73.04 kJ/mol
Answer:
Solid metal
Explanation:
The reduced form of metal ions is the metal in elemental state (simple substance). So, if you have a solution with metal ions and they are reduced, you probably will see the deposition of the metal. For example: if you have a solution with sodium ions (Na⁺), and the ions are then reduced, you will see the aparition of a solid phase of metallic sodium (Na(s)), according to the following half-reaction:
Na⁺ + e- → Na(s)
