Question

Calculate how far ahead of the drop zone a pilot would have needed to drop humanitarian aid packages if the delivery occurred at a speed of Mach 0.74 and an altitude of 10000 to avoid enemy fire

Answer 1

Answer:

S = 11488.42 m

Explanation:

Given,

The speed of the jet, v = 0.74 Mach

                                     = 253.82 m/s

The altitude of the jet, h = 10000 m

Since the jet is travelling horizontally, the vertical component of velocity Vy = 0

The equation for a projectile projected from a height h is given by,

                                  S = Vx [Vy + √(Vy² +2gh)] / g

Since Vy = 0

                                   S = Vx √(Vy² +2gh) / g

                                       = 253.82 x √(2 x 9.8 x 10000) / 9.8

                                       = 11488.42 m

Hence, the humanitarian aid package should be delivered ahead of distance, S = 11488.42 m