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kondaur [170]
3 years ago
15

A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball

of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?
Physics
2 answers:
Masteriza [31]3 years ago
8 0

Answer:

( B )  The first ball is made of a material with a higher specific heat.

Explanation:

kobusy [5.1K]3 years ago
3 0

Explanation:

q = mCΔT

where q is heat,

m is mass,

C is specific heat capacity,

and ΔT is temperature change.

For the first ball:

2500 J = (100 g) C (90°C − 25°C)

C = 0.385 J/g/°C

For the second ball:

5000 J = (200 g) C (90°C − 25°C)

C = 0.385 J/g/°C

The two metals have the same specific heat, and are likely the same metal (possibly copper or zinc).

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When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 49.
UkoKoshka [18]

Answer:

1.1397 Nm

Explanation:

When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth.

If the muscle generates a force

F =  49.5 N and r = 2.65 cm , then the torque is equal to rF

we see that r = 2.65 cm = 0.0265 m

therefore

torque = 0.0265 x 49.5

= 1.1397 Nm

4 0
2 years ago
In the diagram below, point A is southwest of point B. Jaleh walks for 400 seconds along path 1, going from point A to point B.
timama [110]

Answer:

C

Explanation:

velocity = displacement (m) / change of time (s)

velocity = (400 + 300) / (100 + 400)

velocity = 1.4 m/s

4 0
1 year ago
Read 2 more answers
A wheel of radius 25cm has eight spokes. It is mounted on a fixed axle and is rotating at a constant angular speed w. You shoot
spayn [35]

Explanation:

We will assume that the rim of the wheel is also very thin, like the spokes. The distance <em>s</em><em> </em><em> </em>between the spokes along the rim is

s = \frac{1}{8}C = \frac{1}{8}(2\pi)(0.25\:\text{m}) = 0.196\:\text{m}

The 20-cm arrow, traveling at 6 m/s, will travel its length in

t = \dfrac{0.2\:\text{m}}{6\:\text{m/s}} = \dfrac{1}{30}\:\text{s}

The fastest speed that the wheel can spin without clipping the arrow is

v = \dfrac{s}{t} = \dfrac{0.196\:\text{m}}{\left(\dfrac{1}{30\:\text{s}}\right)} = 5.9\:\text{m/s}

The angular velocity \omega of the wheel is given by

\omega = \dfrac{v}{r} = \dfrac{5.9\:\text{m/s}}{0.25\:\text{m}} = 23.6\:\text{rad/s}

In terms of rev/s, we can convert the answer above as follows:

23.6\:\dfrac{\text{rad}}{\text{s}}×\dfrac{1\:\text{rev}}{2\pi\:\text{rad}} = 3.8\:\text{rev/s}

As you probably noticed, I did the calculations based on the assumption that I'm aiming for the edge of the wheel because this is the part of the wheel where a point travels a longer linear distance compared to ones closer to the axle, thus giving the arrow a better chance to pass through the wheel without getting clipped by the spokes. If you aim closer to the axle, then the wheel needs to spin slower to allow the arrow to get through without hitting the spokes.

3 0
2 years ago
A car accelerated from rest in 3.07s. During this time, the car went 46m forward. What was its acceleration?
kari74 [83]
Vi=0
T=3.07s
D=46m
A=?
A=2(d)/t ^2
2(46)/3.07^2=9.8m/s^2
8 0
2 years ago
What is Newton's third law of motion?​
zzz [600]
<h2>Answer : </h2>

Newton's Third law of motion states :

" Every action has an equal and opposite reaction "

i.e If a force is applied by an object A on another object B then that object B also exerts a foce on object A, that is of same magnitude and opposite direction to the force applied by object A.

Ex - A book on a table exerts gravitational force on the table and table exerts back a normal force on the book.

3 0
1 year ago
Read 2 more answers
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