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3 years ago

Which is an action/reaction force pair? check all that apply.

Physics

1 answer:

Vesna [10]3 years ago

3 0

Answer:

According to Newton's third law, for every action force there is an equal (in size) and opposite (in direction) reaction force. Together, these two forces exerted upon two different objects form the action-reaction force pair.

Explanation:

Sana makatulong ^_^

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Question 2 (1 point)

Vesna [10]

Answer:

400m

Explanation:

use formula

velocity = displacement /time

8 0

3 years ago

In the attached position versus time graph what is the magnitude of average velocity for the entire 19 seconds of the motion. An

evablogger [386]

According to the plot, the positions at time <em>t</em> = 0 s and <em>t</em> = 19 s are -1 m and -2 m, respectively. So the average velocity for the 19-s interval is

$v_{\rm ave} = \dfrac{-2\,\mathrm m - (-1\,\mathrm m)}{19\,\mathrm s} = -\dfrac1{19}\dfrac{\rm m}{\rm s}\approx \boxed{-0.05\dfrac{\rm m}{\rm s}}$

8 0

3 years ago

What is the frequency of a wave that has a wavelength of 0.39 m and a speed

gogolik [260]

Answer:

<h3>The answer is option B</h3>

Explanation:

The frequency of a wave can be found by using the formula

$f = \frac{c}{ \lambda} \\$

where

c is the velocity

From the question

wavelength = 0.39 m

c = 86 m/s

We have

$f = \frac{86}{0.39} \\ = 220.512820...$

We have the final answer as

Hope this helps you

7 0

4 years ago

A driver notices that her 1280 kg car slows down from 92 km/h to 68 km/h in about 7.5 s on the level when it is in neutral. Appr

sweet-ann [11.9K]

Answer:

P = 25299.75 watts

Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts

Explanation:

Given;

Mass of car m = 1280kg

initial speed v1 = 92km/h = 92×1000/3600 m/s= 25.56m/s

Final speed v2 = 68km/h = 68×1000/3600 m/s= 18.89m/s

time taken t = 7.5s

Change in the kinetic energy of the car within that period;

∆K.E = 1/2 ×mv1^2 - 1/2 × mv2^2

∆K.E = 0.5m(v1^2 -v2^2)

Substituting the values, we have;

∆K.E = 0.5×1280(25.56^2 - 18.89^2)

∆K.E = 189748.16J

Power used during this Change;

Power P = ∆K.E/t

Substituting the values;

P = 189748.16/7.5

P = 25299.75 watts

Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts

7 0

3 years ago

Larry , Moe, and Curly are pushing on a 25 kg crate. The crate is sitting on a horizontal floor, and the coefficient of kinetic

monitta

Answer:

2 m/s².

Explanation:

The forces acting on the crate have been shown in the figure below.

Net force acting on the crate in the horizontal direction = 400 - 250 = 150 N towards right.

For the forces of vertical direction we can write,

Normal force = 150 + Mg = 150 + 250 = 400 N (here g = 10 m/s² have been taken)

The magnitude of frictional force that will act on the crate = μ × Normal force

So, Frictional force = 0.25 × 400 = 100 N

Thus, the net force that will cause acceleration in the crate will be

Force in the right direction - frictional force

= 150 - 100 = 50 N

As we know,

Acceleration = $\frac{Force}{Mass}$ = $\frac{50}{25}$ = 2 m/s²

So, the net acceleration in the crate will be 2 m/s².

7 0

4 years ago