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Ivahew [28]
3 years ago
7

A turntable of radius R1 is turned by a circular rubberroller of radius R2 in contact with it at their outeredges. What is the r

atio of their angular velocities,ω1 / ω2 ?
Physics
1 answer:
Gwar [14]3 years ago
5 0

Answer:

The  ratio is  \frac{w_1}{w_2}  =  \frac{R_2}{R_1}

Explanation:

From the question we are told that

   The first radius is R_1

    The  second radius is  R_2

   

Generally the angular speed of the turntable is mathematically represented as

       w_1  =  \frac{ v_k }{R_1 }

Generally the angular speed of the rubber roller is mathematically represented as

        w_2 =  \frac{ v_k }{R_2 }

Where v_k is the velocity of both turntable and  rubber roller

So

    \frac{w_1}{w_2}  =  \frac{\frac{v_k}{R_1} }{\frac{v_k}{R_2} }

    \frac{w_1}{w_2}  =  \frac{R_2}{R_1}

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