Question

A turntable of radius R1 is turned by a circular rubberroller of radius R2 in contact with it at their outeredges. What is the ratio of their angular velocities,ω1 / ω2 ?

Answer 1

Answer:

The  ratio is  $\frac{w_1}{w_2} = \frac{R_2}{R_1}$

Explanation:

From the question we are told that

   The first radius is $R_1$

    The  second radius is  $R_2$

   

Generally the angular speed of the turntable is mathematically represented as

       $w_1 = \frac{ v_k }{R_1 }$

Generally the angular speed of the rubber roller is mathematically represented as

        $w_2 = \frac{ v_k }{R_2 }$

Where $v_k$ is the velocity of both turntable and  rubber roller

So

    $\frac{w_1}{w_2} = \frac{\frac{v_k}{R_1} }{\frac{v_k}{R_2} }$

    $\frac{w_1}{w_2} = \frac{R_2}{R_1}$