Answer:
Power = 15[W]
Explanation:
This problem can be solved using the work definition.
Work is equal to the product of the force by the distance, for this problem we have:
F = force = 30 [N]
d = distance = 30 [m]
w = work = F * d = 30*30 = 900 [J], "units in joules"
The power is defined as the work done in an interval of time.
P = w / t
where:
t = time [s]
therefore
P = w / t
P = 900 / 6
P = 150 [W] "units in watts"
I’m almost certain it’s C
Answer:
The total force is most nearly 940,000lbf
Explanation:
Total force = specific weight × volume
Volume = length × width × depth = 10ft × 30ft × 50ft = 15,000ft^3
Total force = 62.4lbf/ft^3 × 15,000ft^3 = 936,000lbf which is most nearly 940,000lbf
Answer:
We learned in the previous section that temperature is proportional to the average kinetic energy of atoms and molecules in a substance, and that the average internal kinetic energy of a substance is higher when the substance’s temperature is higher.
If two objects at different temperatures are brought in contact with each other, energy is transferred from the hotter object (that is, the object with the greater temperature) to the colder (lower temperature) object, until both objects are at the same temperature. There is no net heat transfer once the temperatures are equal because the amount of heat transferred from one object to the other is the same as the amount of heat returned. One of the major effects of heat transfer is temperature change: Heating increases the temperature while cooling decreases it. Experiments show that the heat transferred to or from a substance depends on three factors—the change in the substance’s temperature, the mass of the substance, and certain physical properties related to the phase of the substance.
The equation for heat transfer Q is
Q = mcΔT,
Explanation:
pls brainliest
Explanation:
Given that,
(a) Work done by the electric field is 12 J on a 0.0001 C of charge. The electric potential is defined as the work done per unit charged particles. It is given by :
(b) Similarly, same electric field does 24 J of work on a 0.0002-C charge. The electric potential difference is given by :
Therefore, this is the required solution.