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Arada [10]
3 years ago
5

What would happen if you touched a flask during an endothermic reaction?

Chemistry
1 answer:
max2010maxim [7]3 years ago
5 0
The heat from your hand would be absorbed by the (assumed) colder flask, since an endothermic reaction means that the reaction requires an absorption of heat as opposed to an exothermic reaction, which releases heat.
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Calculate the number of moles of BaF2 in a 10.0 g sample of BaF2.
UkoKoshka [18]

Answer:

The number of moles = 0.06 moles

Explanation:

i) Formula

Number of moles = Mass of the sample ÷ Molar masses of the substances

ii) Number of moles = 10.0 ÷ (137)+(19×2)

= 10.0 ÷ 175

= 0.06 moles

5 0
3 years ago
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Can someone please help me with this?
yaroslaw [1]

Answer:

Lonic.an electron will be transferred from potassium to the chlorine atom

3 0
3 years ago
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Which reactions are single displacement reactions? 2NaBr + CaF2 → 2NaF + CaBr2 SnO2 + 2H2 → Sn + 2H2O 4Na + O2 → 2Na2O 2KClO3 →
r-ruslan [8.4K]

Answer : The correct options are, SnO_2+2H_2\rightarrow Sn+2H_2O and 2Al+6HCl\rightarrow 2AlCl_3+3H_2

Explanation :

Single displacement reaction : It is a type of chemical reaction in which the more reactive element displaces the less reactive element.

Option A reaction : 2NaBr+CaF_2\rightarrow 2NaF+CaBr_2

It is an example of double displacement reaction because in this reaction a positive cation and a negative anion of the two reactants exchange their places to form two new products.

Option B reaction : SnO_2+2H_2\rightarrow Sn+2H_2O

It is an example of single displacement reaction.

Option C reaction : 4Na+O_2\rightarrow 2Na_2O

It is an example of combination reaction because in this reaction two reactants react to give a single product.

Option D reaction : 2KClO_3\rightarrow 2KCl+3O_2

It is an example of decomposition reaction because in this reaction a single reactant decomposes into two or more products.

Option E reaction : 2Al+6HCl\rightarrow 2AlCl_3+3H_2

It is an example of single displacement reaction because in this reaction the most react element, aluminium displaces the less reactive element, hydrogen.

Hence, the options B and E are single displacement reactions.

5 0
4 years ago
Which is of the following is the answer for reactions demonstrates a synthesis reaction?
andrew-mc [135]
The answer is D. This is because a synthesis reaction is when two elements combined to make a product (ex. A+B= AB). Hope this helps!
3 0
3 years ago
Calculate the radius of tantalum (Ta) atom, given that Ta has a BCC crystal structure, a density of 16.6 g/cm, and an atomic wei
Ivahew [28]

Answer:

The radius of tantalum (Ta) atom is R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm

Explanation:

From the Body-centered cubic (BBC) crystal structure we know that a unit cell length <em>a </em>and atomic radius <em>R </em>are related through

a=\frac{4R}{\sqrt{3} }

So the volume of the unit cell V_{c} is

V_{c}= a^3=(\frac{4R}{\sqrt{3} } )^3=\frac{64\sqrt{3}R^3}{9}

We can compute the theoretical density ρ through the following relationship

\rho=\frac{nA}{V_{c}N_{a}}

where

n = number of atoms associated with each unit cell

A = atomic weight

V_{c} = volume of the unit cell

N_{a} =  Avogadro’s number (6.023 \times 10^{23} atoms/mol)

From the information given:

A = 180.9 g/mol

ρ = 16.6 g/cm^3

Since the crystal structure is BCC, n, the number of atoms per unit cell, is 2.

We can use the theoretical density ρ to find the radio <em>R</em> as follows:

\rho=\frac{nA}{V_{c}N_{a}}\\\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}

Solving for <em>R</em>

\rho=\frac{nA}{(\frac{64\sqrt{3}R^3}{9})N_{a}}\\\frac{64\sqrt{3}R^3}{9}=\frac{nA}{\rho N_{a}}\\R^3=\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}} \\R=\sqrt[3]{\frac{nA}{\rho N_{a}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}

Substitution for the various parameters into above equation yields

R=\sqrt[3]{\frac{2\cdot 180.9}{16.6\cdot 6.023 \times 10^{23}}\cdot \frac{1}{\frac{64\sqrt{3}}{9}}}\\R = 1.43 \times 10^{-8} \:cm = 0.143 \:nm

7 0
3 years ago
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