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Arada [10]
3 years ago
5

What would happen if you touched a flask during an endothermic reaction?

Chemistry
1 answer:
max2010maxim [7]3 years ago
5 0
The heat from your hand would be absorbed by the (assumed) colder flask, since an endothermic reaction means that the reaction requires an absorption of heat as opposed to an exothermic reaction, which releases heat.
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disa [49]

Answer:

atoms

have a nice day!

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Beryllium has 4 electrons
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A sample of brass is put into a calorimeter (see sketch at right) that contains of water. The brass sample starts off at and the
Ierofanga [76]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The specific heat is  c_b  = 0.402 J / g \cdot ^oC

Explanation:

From the question we are told that

    The mass of  the sample is  m = 54.4 \ g

     The mass of the water is  m_w = 150.0 \ g

     The initial temperature of the sample is  T_i  = 95.1 ^oC

     The initial temperature of the water is  T_{w_i} =  15^oC

     The final temperature of the water is  T  =  17.6 ^oC

Note the final temperature of water is equal to the final temperature of brass sample

    The pressure is  P =1 \ atm

Generally for according to the law of energy conservation

    The heat lost by sample  =  The heat gain by water

   

The heat lost by brass sample is  mathematically evaluated as    

          H_L  =  m * c_b  *  [T_i - T]

Where c_b is the specific neat of the brass sample

The heat gained  by water is  mathematically evaluated as          

        H_g  = m_w *c_w * [T_w - T ]

where c_w is the specific heat of water which has a constant value of  

     c_w =  4.186  joule/gram

So

    H_L  =  H_g \ \equiv m* c_b  * [T_i -T] =  m_w * c_w * [T - T_w]

substituting values

    52.4 * c_b  * [95.1  - 17.6] =  150 * 4.186 * [ 17.6 - 15.0]

    c_b  = 0.402 J / g \cdot ^oC

4 0
4 years ago
What best describes the dropping height of a ball that bounced back up to a height of 45 centimeters?
katen-ka-za [31]

Answer:

I don't know and I don't understand

Explanation:

I don't know and I don't understand

sorry

sorry for not being able to answer your question

3 0
4 years ago
The ksp of strontium carbonate, srco3, is 5.60 × 10-10. calculate the solubility of this compound in g/l.
alina1380 [7]
The solubility product constant of a compound is calculated by the product of its corresponding ion concentration. The dissociation reaction would be as follows:

SrCO3 = Sr2+ + (CO3)2-

Ksp = [Sr2+] [CO3] = <span>5.60 × 10^-10
</span>5.60 × 10^-10 = x^2
x = 2.37x10^-5 mol/L = 3.49x10^-3 g/L

7 0
4 years ago
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