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pishuonlain [190]
3 years ago
6

All organisms have the same number of cellsA. trueB. false​

Chemistry
2 answers:
denis-greek [22]3 years ago
8 0
The answer is B because not all organisms have the same number of cells
MakcuM [25]3 years ago
4 0

B. false is the answer of this question

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Its b im pretty sure
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I need help with number two too?
KIM [24]

1. 20s, 22s, and 30s... height is the highest.

2. 34s, 38s, and 41s..... height is at its lowest.


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The chemical equation of photosynthesis includes 6O2. What does the small number after the O represent?
blondinia [14]
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3 years ago
The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0
3 years ago
Perform the following mathematical operation and report the answer to the correct number of significant figures? ( I have watche
professor190 [17]

0.008 ÷ 51.3 = 0.0002

Sig Figs

1

0.0002

Decimals

4

0.0002

Scientific Notation

2 × 10-4

E-Notation

2e-4

Words

zero point zero zero zero two

I HOPE I HELP

7 0
3 years ago
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