Answer:
12.14 cm
Explanation:
mass, m = 15.5 kg
frequency, f = 9.73 Hz
maximum amplitude, A = 14.6 cm
t = 1.25 s
The equation of the simple harmonic motion
y = A Sin ωt
y = A Sin (2 x π x f x t)
put, t = 1.25 s, A = 14.6 cm, f = 9.73 Hz
y = 14.6 Sin ( 2 x 3.14 x 9.73 x 1.25)
y = 14.6 Sin 76.38
y = 12.14 cm
Thus, the displacement of the particle from the equilibrium position is 12.14 cm.
Answer:
(B) tightly packed protons and neutrons
Explanation:
- Nucleus of any atom is the dense central part of any atom.
- It consists of two sub-atomic particle namely proton and neutron.
- These sub-atomic parts are tightly packed in nucleus which makes the nucleus dense .
- This dense nucleus is responsible for most of the mass of atom.
- The atomic mass for any atom is decided by sum of the mass of proton and neutron
Thus, correct answer is
(B) tightly packed protons and neutrons
Answer:
I have answer with explanations in each of the six (6) special cases.
Explanation:
Please find attached the detailed solution to all your questions.
Answer:
You are right correct option is D.
