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Leona [35]
3 years ago
13

Identify the correct charge of each atomic particle

Chemistry
2 answers:
Olegator [25]3 years ago
8 0

Answer : The correct option is, (B) Electron = negative, proton = positive, neutron = no charge

Explanation :

As we know that an atom is the smallest unit of a matter that consist of three subatomic particles which are electrons, protons and neutrons.

The protons and the neutrons are located inside the nucleus or center of the nucleus where the mass of the an atom is concentrated and the electrons are located around the nucleus.

The protons are positively charged, the electrons are negatively charged and the neutrons are neutral that means it has no charge.

Hence, the correct option is, (B) Electron = negative, proton = positive, neutron = no charge

MA_775_DIABLO [31]3 years ago
7 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

There are 3 sub-atomic particles present in an atom. They are: Electrons, protons and neutrons.

  1. <u>Electrons:</u> They are negatively charged particles and are present around the nucleus in the orbits.
  2. <u>Protons:</u> They are positively charged particles and are present inside the nucleus of an atom.
  3. <u>Neutrons:</u> They are neutral particles which means they do not carry any charge. They are present in the nucleus of an atom.

Hence, the correct answer is Option B.

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3. How much energy is needed to raise 45 grams of water from 40°C to 115 °C?
Dafna1 [17]

Answer:

Q = 114349.5 J

Explanation:

Hello there!

In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:

Q_1=45g*4.18\frac{J}{g\°C}*(100\°C-40\°C)=11286J\\\\Q_2=45g* 2260 \frac{J}{g} =101700J\\\\Q_3=45*2.02\frac{J}{g\°C}*(115\°C-100\°C)=1363.5J

Thus, the total energy turns out to be:

Q_T=11286J+101700J+1363.5J\\\\Q_T=114349.5J

Best regards!

5 0
3 years ago
Which of the following is an element?
Kryger [21]

Oxygen is a chemical element with symbol O and atomic number 8. Classified as a nonmetal, Oxygen is a gas at room temperature.

8 0
3 years ago
Which of these is a chemical property? color, compressibility, heat of combustion, malleability
Flauer [41]
Chemical changes only happen when the object changes form. Color is a physical property because you're not changing the object that you have, compressibility is also a physical property because you still have the same substance before and sfter, malleability again is another physical. Heat of combustion is physical, when you burn things it changes the substance. :)
6 0
3 years ago
Read 2 more answers
Isotopes that decay with a nuclear break-up and emit a significant amount of energy are said to be ________.
podryga [215]

Answer to this is Radioactive isotopes.

Isotopes are the species of the same element having different atomic masses that means the number of protons remains the same but number of neutrons do differ. For example _{1}^{2}\textrm{H} and _{1}^{3}\textrm{H} are the two isotopes of Hydrogen (_{1}^{1}\textrm{H} ).

Radioactive isotopes are the isotopes which release some kind of energy in the form of alpha particles, beta particles or gamma radiation. Examples of each of the decay processes are :

Alpha Decay: In this decay one alpha particle having atomic mass 4 and atomic number 2 or we can say a He molecule will come out. _{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_{2}^{4}\alpha

Beta Decay: In this decay a \beta particle is emitted increasing the atomic number of the reactant by 1 unit.

_{Z}^{A}\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+_{-1}^{0}\beta

Gamma Radiation: In this type of reaction only radiation is emitted out which does not change the original molecule.

_{Z}^{A}\textrm{X}\rightarrow _{Z}^{A}\textrm{X}+\gamma\text{ radiation}

3 0
3 years ago
What is the concentration of a solution in which 15 grams of sugar is dissolved in 0.2 L of water?
Margaret [11]

Answer:

0.2 M

Explanation:

Step 1: Given data

  • Mass of sugar (sucrose): 15 g
  • Volume of water: 0.2 L (we will assume it is the volume of the solution)

There are different ways to express the concentration of a solution. We will calculate molarity, which is one of the most used.

Step 2: Calculate the moles of sucrose

The molar mass of sucrose is 342.3 g/mol.

15 g × 1 mol/342.3 g = 0.044 mol

Step 3: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = 0.044 mol/0.2 L = 0.2 M

7 0
3 years ago
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