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Leona [35]
3 years ago
13

Identify the correct charge of each atomic particle

Chemistry
2 answers:
Olegator [25]3 years ago
8 0

Answer : The correct option is, (B) Electron = negative, proton = positive, neutron = no charge

Explanation :

As we know that an atom is the smallest unit of a matter that consist of three subatomic particles which are electrons, protons and neutrons.

The protons and the neutrons are located inside the nucleus or center of the nucleus where the mass of the an atom is concentrated and the electrons are located around the nucleus.

The protons are positively charged, the electrons are negatively charged and the neutrons are neutral that means it has no charge.

Hence, the correct option is, (B) Electron = negative, proton = positive, neutron = no charge

MA_775_DIABLO [31]3 years ago
7 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

There are 3 sub-atomic particles present in an atom. They are: Electrons, protons and neutrons.

  1. <u>Electrons:</u> They are negatively charged particles and are present around the nucleus in the orbits.
  2. <u>Protons:</u> They are positively charged particles and are present inside the nucleus of an atom.
  3. <u>Neutrons:</u> They are neutral particles which means they do not carry any charge. They are present in the nucleus of an atom.

Hence, the correct answer is Option B.

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A weather balloon is filled with helium that occupies a volume of 5.37 104 L at 0.995 atm and 32.0°C. After it is released, it r
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Answer:

The new volume is 63583 L

Explanation:

Step 1: Data given

The initial volume of the balloon = 5.37 * 10^4 L

The initial pressure = 0.995 atm

The initial temperature = 32.0 °C = 305.15 K

The pressure decreased to 0.720 atm

The temperature decreased to -11.7 °C = 261.45 K

Step 2: Calculate the new volume

P1*V1 / T1 = P2*V2/T2

⇒with P1 = the initial pressure = 0.995 atm

⇒with V1 = the initial volume = 5.37 *10^4 L

⇒with T1 = the initial temperature = 305.15 K

⇒with P2 = the decreased pressure = 0.720 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the decreased temperature : 261.45 K

(0.995 * 5.37*10^4)/305.15 = (0.720 * V2) / 261.45

V2 = 63583 L

The new volume is 63583 L

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hope this helps


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