Question

Find the terminal point on the unit circle determined by pi radians.

Answer 1

Answer:

Terminal points

$(x,y) = (\frac{1}{\sqrt{2} }) , (\frac{-1}{\sqrt{2} })$

Step-by-step explanation:

According to the question, it is provided that

$\theta = \frac{7\pi}{4}$

Now

$x = 1. cos (\frac{7\pi}{4})\\\\ = cos (2\pi - \frac{\pi}{4})\\\\= cos \frac{\pi}{4} \\\\= \frac{1}{\sqrt{2} }$

$y = 1. sin (\frac{7\pi}{4})\\\\ = sin (2\pi - \frac{\pi}{4})\\\\= -sin \frac{\pi}{4} \\\\= \frac{-1}{\sqrt{2} }$

Now

$(x,y) = (\frac{1}{\sqrt{2} }) , (\frac{-1}{\sqrt{2} })$

These two represents the terminal points

We simply applied the above equations and then equate these two equations to determine the terminal points and therefore the same is to be considered

It could be figure out by using the x and y points

Therefore the two shows the terminal points