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777dan777 [17]
3 years ago
10

If a ball speeds up as it is rolling down a hill, the forces acting on it must be -

Physics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

the forces acting on it must be strong because gravity is pushing the ball down

Explanation:

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andrey2020 [161]

Answer: you want your input force harder

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Is the alien theory a scientific claim? Why or why not?
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I'm not sure what the alien Theory says or if there really is such a theory. If the theory says that aliens definitely exist and that they have visited Earth in the past then the theory is totally and completely without any kind of support. It's not scientific in any way because there is no evidence for such a claim. It may be thought to be probable but no solid evidence has ever been presented.
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3 years ago
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The wavelength of a wave on a string is 1.2 meters. If the speed of the wave is 60 m/s, what is the wave frequency? 5 points 0.2
vagabundo [1.1K]

Answer:

50 Hz is the answer because 60 m/s divided by 1.2 meters is 50.

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3 years ago
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easy bio A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 438 N and have a center of
goblinko [34]

Answer:

1.034 m above the floor

Explanation:

The location of center of body for a compound body, when the weights are given is calculated as:

\bar x = \frac{W_1x_1+W_2x_2+W_3x_3+W_4x_4+W_5x_5+.......+Wnx_n}{W_1+W_2W_3W_4W_5+.....+W_n}

where,

\bar x is the center of gravity of the entire body

W = weight of the individual body

x = center of gravity of the individual body

Thus on substituting the values we get,

\bar x = \frac{438\times 1.28+144\times 0.760+87\times 0.250}{438+144+87}

or

\bar x = \frac{691.83}{669}

or

\bar x =1.034m

Hence, <u>the center of gravity of the entire body lies </u><u>1.034 m</u><u> </u><u>above the floor</u>

6 0
3 years ago
An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reach
Gelneren [198K]

Answer:5 m/s^{2}

Explanation:

This problem is related to vertical motion, and the equation that models it is:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

g is the acceleration due gravity in Planet X

Isolating g and taking into account sin(90\°)=1 :

g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

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3 years ago
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